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ICE Princess25 [194]
3 years ago
5

Help on this please

Mathematics
1 answer:
sveta [45]3 years ago
4 0
Answer:

y = 1/6x + 3

Step-by-step explanation:

Q = y = -6x + 1

R is perpendicular to line Q and passes through the point (6, 4)

First graph y = -6x + 1

And then plot (6, 4) on the graph

Next draw a perpendicular line

Finally write the equation of line Q

Q: y = 1/6x + 3
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7nadin3 [17]

Answer:

We also drew a graph with 2 examples.

Step-by-step explanation:

If we have the line segment  CD, we can divide it by 4: 1 as follows:

If point C has the coordinates (x1, z1) and point D has the coordinates (x2, z2), we calculate coordinate the points Y as follows:

y1 = (x2-x1) · 4/5

y2 = (z2-z1) · 4/5

In this way we have obtained the point Y with the coordinates (y1, y2), and the point Y divides the line segment  CD by 4:1.

We also drew a graph with 2 examples.

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pantera1 [17]
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3 years ago
46 Two light houses ash their lights every 30 seconds and 40 seconds respectively. Given that they last ashed together at 10:40
IRISSAK [1]
30,60,90,120
40,80,120

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8 0
3 years ago
Find the solution to the system:
Sliva [168]

Answer:

u = 12, v= 15

Step-by-step explanation:

Given the system of simultaneous equation:

1/6 u− 1/3 v=−3... (1)

0.2u+0.1v=3.9...(2)

Rewriting both equation as fraction

1/6 u− 1/3 v=−3

1/5 u + 1/10 v = 39/10

Multiplying equation (1) by 6 and (2) by 10 we have:

u - 2v = -18... (3)

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Using elimination method, we will first multiply equation (3) by 2 and (2) by 1 to have:

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Subtracting (5) from (6);

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v = -75/-5

v = 15

Substituting v = 15 into equation (3) to get u we have:

u - 2(15) = -18

u - 30 = -18

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The solution to the system of simultaneous equation are u = 12 and v = 15

7 0
3 years ago
What happened to the guy who lost the pie eating contest
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