Hello! I'm having a bit of trouble trying to solve this, could anyone help explain it to me?
2 answers:
<h2>×=64</h2>
Step By Step Explanation:
<h3>

</h3><h3>Step 1</h3>
Calculate 60 to the power of 2 and get 3600.
<h3>

</h3><h3>Step 2</h3>
Use the distributive property to multiply 36 by 36 + ×.
<h3>

</h3><h3>Step 3</h3>
Swap sides so the all variable terms are on the left hand side.
<h3>

</h3><h3>Step 4</h3>
Subtract 1296 from both sides.
<h3>

</h3><h3>Step 5</h3>
Subtract 1296 from 3600 to get 2304.
<h3>

</h3><h3>Step 6</h3>
Divide both side by 36.
<h3>

</h3><h3>Step 7</h3>
Divide 2304 by 36 to get 64
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My Answer is
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</h3>
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Answer:
x + 37 ≥ 65
Step-by-step explanation:
Given:
Money Micah wants = $65
Money Micah had = $37
Find:
Money Micah need
Computation:
Money Micah need(x)
x + 37 ≥ 65
So,
Money Micah need = 65 - 37
Money Micah need = $28
Answer:
Suppose that logb b = x.
bx = b (Use the definition of a logarithm.)
bx = b1
x = 1 (Use the common base property.)
So, logb b = 1.
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Step-by-step explanation:
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