Question

If Triangle ABC is congruent to Triangle SRT, find the possible value(s) for x

Answer 1

Answer:

x = 2 or x = -3

Step-by-step explanation:

Given that ∆ABC ≅ ∆SRT, it follows that their corresponding side lengths are congruent to each other.

Thus:

$RT = BC$

$(x^2 + x) = 6$

Solve for x

$x^2 + x = 6$

Subtract 6 from each side

$x^2 + x - 6 = 6 - 6$

$x^2 + x - 6 = 0$

Factorise

$x^2 + 3x - 2x - 6 = 0$

$x(x + 3) -2(x + 3)$

$(x - 2)(x + 3)$

x = 2 or x = -3