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dybincka [34]
3 years ago
15

EASY PLEASE HELP PLEASE HELP 15 POINTS...PLEASE HELP

Mathematics
2 answers:
Blizzard [7]3 years ago
6 0

Answer:

The y intercept is -2, because that is the point where the line hits the vertical y intercept. The slope is - 1/4

Step-by-step explanation:

olya-2409 [2.1K]3 years ago
3 0

Answer:

slope = -1/4

y-intercept = -2

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Patrick built a robot that is 0.8 meters tall. Adelaide built a robot that is 2 feet 9 inches
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Adelaides Robot is taller.

Step-by-step explanation:

Adelaide's robot is 83.82 centemetres = 0.84 meters

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HELP PLEASE<br> Simplify: -1| 2/3-4| divided by 5/6<br><br> -4<br> -25/9<br> 25/9<br> 4
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-4

Step-by-step explanation:

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2 years ago
Lee and barry play a trivia game in which questions are worth different numbers of points. If a question is answered correctly,
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1st) 275+70-50      Lastly: Subtract  -350 - 295 = - 55
       
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3 years ago
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A computer chess game and a human chess champion are evenly matched. They play ten games. Find probabilities for the following e
AleksAgata [21]

Answer:

(a) The probability that each of them win five games is 0.2461.

(b) The probability that the computer wins seven games is 0.1172.

(c) The probability that the human wins at least 7 games is 0.1711.

Step-by-step explanation:

Let the random variable <em>X</em> = the human wins a chess game.

The probability that the human wins a game is, P (X) = <em>p</em> = 0.50.

The number of games played by the computer and the human is, <em>n </em>= 10.

The random variable X\sim Bin(n = 10,p=0.50)

The probability distribution of the Binomial random variable <em>X</em> is:

P (X=x)={n\choose x}p^{x}(1-p)^{n-x}={10\choose x}(0.50)^{x}(1-0.50)^{10-x}

(a)

If both the computer and the human wins five games each then the probability of the human winning 5 games is:

P (X=5)={10\choose 5}(0.50)^{5}(1-0.50)^{10-5}\\=252\times 0.03125\times0.03125\\=0.246094\\\approx 0.2461

Thus, the probability that each of them win five games is 0.2461.

(b)

If the computer wins 7 games then the number of games won by the human is, 10 - 7 = 3.

P (Computer winning 7 games) = P (Human winning 3 games)

The probability that the human wins 3 games is:

P (X=3)={10\choose 3}(0.50)^{3}(1-0.50)^{10-3}\\=120\times 0.125\times0.0078125\\=0.1171875\\\approx 0.1172

Thus, the probability that the computer wins seven games is 0.1172.

(c)

Compute the probability that the human wins at least 7 games as follows:

P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\={10\choose 7}(0.50)^{7}(1-0.50)^{10-7}+{10\choose 8}(0.50)^{8}(1-0.50)^{10-8}\\+{10\choose 9}(0.50)^{9}(1-0.50)^{10-9}+{10\choose 10}(0.50)^{10}(1-0.50)^{10-10}\\=0.1172+0.044+0.009+0.0009\\=0.1711

Thus, the probability that the human wins at least 7 games is 0.1711.

5 0
3 years ago
Work out the simultaneous equation for 3x+ 4 = 40<br> 9x– 7y = -13
butalik [34]

Answer:

Step-by-step explanation:

symmmmmmmmmmm

4 0
4 years ago
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