( f o<span> g)(x) = f (g(x))</span><span>
</span><span> = f (–x2 + 5)</span><span>
</span> = 2( ) + 3 ... setting up to insert the input formula<span>
</span><span> = 2(–x2 + 5) + 3</span><span>
</span><span> = –2x2 + 10 + 3</span><span>
</span> = <span>–2x2 + 13</span><span> </span>
A small rocky body orbiting the sun
No,Rock haven't cells because rock is non living thing.
Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
The correct option among all the options given is A the bald eagle.