1/3(2b + 9) = 23(b + 9/2)
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
From the given information:
The number of children that were randomly allocated to each vaccination group; n₁ = 200,000
No of polio cases X₁ = 57
Now, in the vaccine group:
the proportion of polio cases is:
= 0.000285
The number of children that were randomly allocated to the placebo group, n₂ = 200,000
No of polio cases X₂ = 142
In the placebo group
the proportion of polio cases is:
Null and alternative hypothesis is computed as follows:
H₀: There is no difference in the proportions of polio cases between both groups.
H₁: There is a difference in the proportions of polio cases between both groups.
Let assume that the level of significance ∝ = 0.05
The test statistic can be computed as:
Z = - 6.03
P-value = 2P(Z < -6.03)
From the Z - tables
P-value = 2 × 0.0000
= 0.000
We reject the H₀ provided that P-value is very less.
Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.
Answer:
b) Both 1,004 and 251 are greater than 10.
Step-by-step explanation:
p = 0.80
n = 1255
In order to use CLT the distribution of should have np and n(1-p) greater than 10.
np = 1255*0.80
np = 1004
n(1-p) = 1255*0.20
n(1-p) = 251.00
Since Both 1004 and 251 are greater than 10,