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gavmur [86]
2 years ago
10

PLEASE ANSWER ASAP THANKSSS :)

Mathematics
1 answer:
OLga [1]2 years ago
5 0

Answer:

The first one ( $3 + 3 + 3 + 3 = 12, so Sal can afford the gas. )

Step-by-step explanation:

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Original grade: 80<br> New grade: 100<br> Find the percent of increase.<br> 107
Kipish [7]

Step-by-step explanation:

Based on the given conditions,

Formulate:(100-80)÷80

Calculate the sum or difference:20/80

Cross out the common factor:1/4

Multiply a number to both the numerator and the denominator:1/4×25/25

Write as a single fraction :25/4×25

Calculate the product or quotient :25/100

Rewrite a fraction with denominator equals 100 to a percentage:25%

Answer : 25%

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2 years ago
Sandesh bought two books for Rs 480.He sold them to attain 19% profit on one and 15% loss on the other. Calculate his final gain
slamgirl [31]

Answer:

answer = profit 14.166%

7 0
2 years ago
A dolphin is 42 feet underwater and ascends at a constant rate for 14 seconds until it reaches the surface. Identify and interpr
Cloud [144]
Ok so, based on the graph lets say that x = seconds and  y = depth of dolphin. the interception in both points is when they are at 0 i.e when x is equals 0 and y equals 0. So At 0 seconds, the dolphin is 42 feet below the surface. So we say that x = 0, y = -42 and then the y intercepts = -42 so the point of interception is(0 (seconds),-42(depth of the dolphin)) When the clock says it's 14 seconds, the dolphin is even with the surface (0 below the surface this time). So we say that x = 14, y = 0. In this case The x intercept = 14 (14,0). But we need to calculate The slope with the formula= (y2 - y1)/(x2 - x1) = 42/14 = 3. Therefore, the formula for this line is y = 3x - 42.
3 0
3 years ago
A 30 minute TV program consist of three commercials, each 2 1/2 minutes long, and four equal length entertainment segments. How
maksim [4K]
Each one would be 5 minutes because 2 1/2 Times 4 = 10 minutes. You would have 20 minutes remaining so divide 20 by how many segments there are, which is 4 to get 5
8 0
3 years ago
In Lake Erie, walleye fish are abundant. The lengths of walleyes follow a Normal distribution with a mean of 31 inches and a sta
AlladinOne [14]

Answer:

d. Approximately 84% of walleyes have lengths less than 34.6 inches.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 31

Standard deviation = 3.6

a. Approximately 32% of walleyes have lengths less than 27.4 inches.

27.4 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. Of the other 32% more than 1 standard deviation from the mean, 16% of the lengths are less than 27.4 and 16% are greather than 31+3.6 = 34.6.

So approximately 16% of walleyes have lengths less than 27.4 inches, which means that this statement is false.

b. Approximately 95% of walleyes have lengths greater than 23.8 inches.

23.8 is two standard deviations below the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviations of the mean. Of the 5% that is more than 2 standard deviations from the mean, 2.5% is greater than 2 standard deviations above the mean(greater than 38.2, in this problem), and 2.5% is lower than 2 standard deviations below the mean(lower than 23.8 in this problem).

So 2.5% of walleyes have lengths lower than 23.8 and 100-2.5 = 97.5% have lengths greater than 23.8, which means that this statement is false.

c. Approximately 16% of walleyes have lengths longer than 38.2 inches.

38.2 is two standard deviations above the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviations of the mean. Of the 5% that is more than 2 standard deviations from the mean, 2.5% is greater than 2 standard deviations above the mean(greater than 38.2, in this problem), and 2.5% is lower than 2 standard deviations below the mean(lower than 23.8 in this problem).

So 2.5% of walleyes have lengths longer than 38.2 inches, which means that this statement is false.

d. Approximately 84% of walleyes have lengths less than 34.6 inches.

34.6 is one standard deviation above the mean.

The empirical rule is symmetric, which means that 50% of the measures are above the mean and 50% of the meausures are below the mean.

Also, 68% of the measures are within 1 standard deviation of the mean. Of those, 34% are between one standard deviation below the mean and the mean, and 34% are between the mean and one standard deviation above the mean.

So, 50% below the mean, plus 34% between the mean and 34.6 means that approximately 84% of the walleyes have lengths less than 34.6 inches, which means that this statement is true.

e. Approximately 2.5% of walleyes have lengths between 31 inches and 34.6 inches.

31 is the mean

34.6 is one standard deviation above the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. Of those, 34% are between one standard deviation below the mean and the mean, and 34% are between the mean and one standard deviation above the mean.

So 34% of walleyes have lengths between 31 inches and 34.6 inches, which means that this statement is false.

5 0
3 years ago
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