![\begin{array}{ccc}48&-&100\%\\54&-&p\%\end{array}\ \ \ |cross\ multiply\\\\48p=54\cdot100\\48p=5400\ \ \ \ |divide\ both\ sides\ by\ 48\\\boxed{p=112.5}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccc%7D48%26-%26100%5C%25%5C%5C54%26-%26p%5C%25%5Cend%7Barray%7D%5C%20%5C%20%5C%20%7Ccross%5C%20multiply%5C%5C%5C%5C48p%3D54%5Ccdot100%5C%5C48p%3D5400%5C%20%5C%20%5C%20%5C%20%7Cdivide%5C%20both%5C%20sides%5C%20by%5C%2048%5C%5C%5Cboxed%7Bp%3D112.5%7D)
Answer: 54 is 112.5% of 48.
Median = Middle number.
_ _ _ _ _ _
I would put
_ _ 4.5 5.5 _ _
2.5 3.5 4.5 5.5 6.5 7.5
Any numbers work so long as the two center ones have a 'happy median' of 5 (the middle place between the two numbers) and so long as they are in numerical order. There are infinitely many possible solutions to this problem. This is one of many possible answers. Hope this helps :)
<h3>
Answer:</h3>
![\boxed{\sf x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20x%20%3D%20%5Cdfrac%7Bc%7D%7Bb%7D%20%5Cquad%20or%20%20%5Cquad%20%5Cdfrac%7B-b%7D%7Ba%7D%7D)
Explanation:
Given expression: (ab)x^2 + (b^2 - ac)x + (-bc) = 0
Here given:
Apply quadratic formula:
![\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad when \ ax^2 + bx + c = 0](https://tex.z-dn.net/?f=%5Csf%20x%20%20%3D%20%5Cdfrac%7B%20-b%20%5Cpm%20%5Csqrt%7Bb%5E2%20-%204ac%7D%7D%7B2a%7D%20%5Cquad%20when%20%20%5C%20ax%5E2%20%2B%20bx%20%2B%20c%20%3D%200)
Insert values:
![\sf x = \dfrac{-(b^2 - ac) \pm \sqrt{(b^2 -ac)^2-4(ab)(-bc)} }{2(ab)}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B-%28b%5E2%20-%20ac%29%20%5Cpm%20%5Csqrt%7B%28b%5E2%20-ac%29%5E2-4%28ab%29%28-bc%29%7D%20%7D%7B2%28ab%29%7D)
![\sf x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2-ac\right)^2+4abbc} }{2ab}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B-b%5E2%20%2B%20ac%20%5Cpm%20%5Csqrt%7B%5Cleft%28b%5E2-ac%5Cright%29%5E2%2B4abbc%7D%20%7D%7B2ab%7D)
![\sf x = \dfrac{-b^2 + ac \pm \sqrt{b^4+2b^2ac+a^2c^2} }{2ab}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B-b%5E2%20%2B%20ac%20%5Cpm%20%5Csqrt%7Bb%5E4%2B2b%5E2ac%2Ba%5E2c%5E2%7D%20%7D%7B2ab%7D)
![\sf x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2+ac\right)^2} }{2ab}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B-b%5E2%20%2B%20ac%20%5Cpm%20%5Csqrt%7B%5Cleft%28b%5E2%2Bac%5Cright%29%5E2%7D%20%7D%7B2ab%7D)
![\sf x = \dfrac{-b^2 + ac \pm( b^2+ac )}{2ab}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B-b%5E2%20%2B%20ac%20%5Cpm%28%20b%5E2%2Bac%20%29%7D%7B2ab%7D)
![\sf x = \dfrac{-b^2 + ac +( b^2+ac )}{2ab} \quad or \quad \dfrac{-b^2 + ac -( b^2+ac )}{2ab}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B-b%5E2%20%2B%20ac%20%2B%28%20b%5E2%2Bac%20%29%7D%7B2ab%7D%20%5Cquad%20or%20%5Cquad%20%5Cdfrac%7B-b%5E2%20%2B%20ac%20-%28%20b%5E2%2Bac%20%29%7D%7B2ab%7D)
![\sf x = \dfrac{2ac}{2ab} \quad or \quad \dfrac{-2b^2}{2ab}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7B2ac%7D%7B2ab%7D%20%5Cquad%20or%20%20%5Cquad%20%5Cdfrac%7B-2b%5E2%7D%7B2ab%7D)
![\sf x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}](https://tex.z-dn.net/?f=%5Csf%20x%20%3D%20%5Cdfrac%7Bc%7D%7Bb%7D%20%5Cquad%20or%20%20%5Cquad%20%5Cdfrac%7B-b%7D%7Ba%7D)
11x = -7y
this is the answer because you combine the x together