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olga nikolaevna [1]
3 years ago
7

3x^2-12+(x-4)(2-x)-(x^2-4x+4)

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

x² + 10x - 24

Step-by-step explanation:

3x² - 12 + (x - 4)(2 - x) - (x² - 4x + 4)

= 3x² - 12 + (2x - x² - 8 + 4x) - x² + 4x - 4

= 3x² - 12 + 2x - x² - 8 + 4x - x² + 4x - 4

= x² + 10x - 24

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Step-by-step explanation:

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A system of 2 linear equations is ___ dimensional. It is a graph of _____ lines. The solutions can be _____ solution if the grap
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Considering High School level question, answer can be written as:


A system of 2 linear equations is [two] dimensional. It is a graph of [two] lines. The solutions can be [unique] solution if the graph intersects. [No] solution if the lines are parallel - meaning they have the same slope, or [Infinitely many] solutions if they are the same line.

Explanation:

when two lines are drawn on a two-dimensional plane then there are only three possible cases:


Case1: lines will intersect

In that case you will get a unique solution at the intersection point.


Case2: lines are parallel but don't touch each other

In that case there will be no point which lies on both lines so No solution.


Case3: lines are overlapping.

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Assume that the engine component of a spacecraft consists of two engines in parallel. If the main engine is 95% reliable, the ba
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a) 0.04

b) 0.19

c) 0.01

d) 0.8

Step-by-step explanation:

Hi,

Let's make our data, considering two rules of probability:

  1. The total probability of any event is 1.
  2. Percentages are converted to decimal.
  • P(M) = 0.95
  • P(M')=0.05
  • P(B)=0.80
  • P(B')=0.20

- where M → Main Engine works, B → Back Up Engine works, M' → Main Engine will not work and B' → Back Up Engine will not work.

<em>Remember for cases with </em><em>and, </em><em>we multiply; for cases with </em><em>or</em><em>, we use addition.</em>

<em />

a) For this part, we know that Main Engine will work and Back-up engine will not work:

P(M' and B): 0.05 x 0.80 = 0.04

b) Back up will not work and Main will work:

P(M and B') = 0.20 x 0.95 = 0.19

c) We know the probability of entire component working, which is 0.99.

So to find the probability of entire component failing, we need to subtract 0.99 from 1. <em>(Since the total probability is always 1)</em>

P(Entire component will fail) = 1 - 0.99 = 0.01

d) This is a typical case of conditional probability, to calculate a conditional probability we use the following formula:  P(A|B) = \frac{P(A\ and\ B)}{P(B)}

Where, P(A|B) means the probability of A, given B.

Simply using this, we calculate the P(B|M'):

P( B\ and\ M') = 0.04  <em>(as calculated in part a)</em>

<em />P(M')=0.05<em> (as calculated for the data)</em>

<em />

Modifying the formula to our needs:<em> </em>P(B|M') = \frac{P(B\ and\ M')}{P(M')}<em />

⇒P(B|M') = \frac{0.04}{0.05} = 0.80 Ans.

I hope this answers all your queries.

8 0
3 years ago
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