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3 years ago

13

Rachel draws a different circle. The radius of Rachel’s circle is 12 the radius of Grace’s circle. Which statement about Rachel’

s circle is true?
(a) The area of Rachel’s circle is 14 the area of Grace’s circle.
(b) The area of Rachel’s circle is 12 the area of Grace’s circle.
(c) The area of Rachel’s circle is 2 times the area of Grace’s circle.
(d) The area of Rachel’s circle is 4 times the area of Grace’s circle.

2 answers:

TiliK225 [7]3 years ago

7 0

Answer:

b

ez

Step-by-step explanation:

Dmitrij [34]3 years ago

5 0

Answer is b because all the other one don’t add up to the picture .

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I think its 20.....

Step-by-step explanation:

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Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for

-Dominant- [34]

Answer:

168

Step-by-step explanation:

The first equation given is $0.50 a +3.75 b= 2071.50$

Where a is number of adult tickets and b is number of student tickets

It is also given that 82 students attended, so we can put "82" in place of "b" and then solve the equation for a:

$10.50a+3.75b=2071.50\\10.50a+3.75(82)=2071.50\\10.50a+307.5=2071.50\\10.50a=2071.50-307.5\\10.50a=1764\\a=\frac{1764}{10.50}\\a=168$

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4 years ago

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Activity 2. Find the equation of the line using Two-Point form,

jasenka [17]

Answer:

1) equation of line is: y-3=0

2) equation of line is: $\mathbf{y-3=-\frac{1}{2}(x-4)}$

3) equation of line is: $\mathbf{y+3=-\frac{4}{3}(x-3}$

4) equation of line is: $\mathbf{y-2=-2(x-2)}$

Step-by-step explanation:

We need to find the equation of the line using Two-Point form.

The general equation of two-point form is: $y-y_1=m(x-x_1)$ where m is slope.

The formula used to calculate slope is: $Slope=\frac{y_2-y_1}{x_2-x_1}$

1. (1,3) and (-2,3)

First finding slope

We have: $x_1=1, y_1=3, x_2=-2, y_2=3$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{3-3}{-2-1}\\Slope=\frac{0}{-3}\\Slope=0\\$

So, equation of line will be:

Using slope m=0 and point (1,3)

$y-y_1=m(x-x_1)\\y-3=0(x-1)\\y-3=0\\$

So, equation of line is: y-3=0

2. (4,3) and (6,2)

First finding slope

We have: $x_1=4, y_1=3, x_2=6, y_2=2$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-3}{6-4}\\Slope=\frac{-1}{2}\\$

So, equation of line will be:

Using slope m= $\frac{-1}{2}$ and point (4,3)

$y-y_1=m(x-x_1)\\y-3=\frac{-1}{2}(x-4)\\y-3=-\frac{1}{2}(x-4)$

So, equation of line is: $\mathbf{y-3=-\frac{1}{2}(x-4)}$

3) (3,-3) and (0,1)

First finding slope

We have: $x_1=3, y_1=-3, x_2=0, y_2=1$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-(-3)}{0-3}\\Slope=\frac{1+3}{-3}\\Slope=-\frac{4}{3}\\$

So, equation of line will be:

Using slope m= $-\frac{4}{3}$ and point (3,-3)

$y-y_1=m(x-x_1)\\y-(-3)=-\frac{4}{3}(x-3)\\y+3=-\frac{4}{3}(x-3)\\$

So, equation of line is: $\mathbf{y+3=-\frac{4}{3}(x-3)}$

4) (2,2) and (4,-2)

First finding slope

We have: $x_1=2, y_1=2, x_2=4, y_2=-2$

$Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-2-2}{4-2}\\Slope=\frac{-4}{2}\\Slope=-2\\$

So, equation of line will be:

Using slope m=-2 and point (2,2)

$y-y_1=-2(x-x_1)\\y-2=-2(x-2)\\$

So, equation of line is: $\mathbf{y-2=-2(x-2)}$

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Brilliant_brown [7]

I believe the answer is 40 when it’s rounded

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