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Wittaler [7]
3 years ago
9

Which expression represents the length of the hypotenuse, c, of the triangle below?

Mathematics
2 answers:
telo118 [61]3 years ago
8 0

Answer:

C) c=\sqrt{a^{2} +b^{2} }

Step-by-step explanation:

The Pythagorean Theorem states that for a right triangle, the relationship between its three sides is a^{2} +b^{2} =c^{2} where a and b are side lengths and c is the length of the hypotenuse. This means that the length of the hypotenuse is c=\sqrt{a^{2} +b^{2} } by taking the square root of both sides to solve for c, making option C correct.

nlexa [21]3 years ago
5 0
Square root a^2 + b^2
The third one from the right
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Candidate C received 15,000 fewer votes than candidate B. If a total of 109,000 votes were cast, how many votes did candidate B
Zina [86]

Answer: Candidate B has 69,500 votes!

Step-by-step explanation:

one easy way to solve this is by dividing 109,000 in half and that gives us

54500 and 54500 but since Candidate C has 15000 less

we subtract 15000 from candidate c and add 15000 from candidate b

which gives us

Candidate C= 39,500 votes

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Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the
Julli [10]

Answer:

a) z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53  

b) p_v =2*P(z

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

\bar X_{1}= 104 represent the mean for 1

\bar X_{2}= 106 represent the mean for 2

\sigma_{1}= 8.4 represent the population standard deviation for 1

\sigma_{2}= 7.6 represent the population standard deviation for 2

n_{1}=80 sample size for the group 1

n_{2}=70 sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0:\mu_{1}=\mu_{2}

H1:\mu_{1} \neq \mu_{2}

The statistic would be given by:

z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=(1)

Part a

Replacing we got:

z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53

Part b

The p value would be given by this probability:

p_v =2*P(z

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

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A;
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zhannawk [14.2K]

Answer:

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romanna [79]

Answer:

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Step-by-step explanation:

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