2 years ago

Can you please solve this problem? It would be greatly appreciated!

Mathematics

1 answer:

qaws [65]2 years ago

5 0

25 pi is the answer is think

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3 years ago

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3 years ago

Read 2 more answers

Solve for x. 5 x − 19 ≤ 1 OR − 4 x + 3 < − 6

k0ka [10]

$5x - 19 \leqslant 1$

change

$\leqslant \: to \: =$

given you

$5x - 19 = 1$

making x the subject by transferring the -19 to the right hand side of the equation

$5x = 19 + 1$

$5x = 20$

dividing through by 5

$\frac{5x}{5} = \frac{20}{5}$

$x = 4$

{ ${x:x \leqslant 4}$ }

also given

$- 4x + 3 < - 6$

change the operation sign to =

$- 4x + 3 = - 6$

$- 4x = - 6 - 3$

$- 4x = - 9$

dividing through by -4

$\frac{ - 4x}{ - 4} = \frac{ - 9}{ - 4}$

$x = \frac{9}{4}$

so the truth set is

{x:x>9/4}.

The < sign changes to > because we divided by a negative number when solving for x

4 0

3 years ago