Write an expression to represent 1 less than the quotient of four and a number X

Kazeer [188]

Star : 10,0
Lightning:7,6
Circle : 10,6
Heart:3,10
Cross:7,8
Triangle:1,4
Moon:10,8
Square:3,0
Diamond:5,0
Music note: 7,6

6 0

3 years ago

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9 lb=_______________oz

Natasha2012 [34]

There are 16 ounces in a pound, so to find the amount of ounces in a certain amount of pounds, all we have to do is multiply the amount of pounds by the amount of ounces there are in one pound.

9 * 16 = 144

There are 144 ounces in 9 pounds.
Hope that helped! =)

8 0

3 years ago

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By law, an industrial plant can discharge not more than 500 gallons of waste water per hour, on the average, into a neighboring

Alisiya [41]

Answer:

We conclude that not more than 500 gallons of wastewater per hour, on average, is discharged into a neighboring lake.

Step-by-step explanation:

We are given that an industrial plant can discharge not more than 500 gallons of wastewater per hour, on average, into a neighboring lake.

Four one-hour periods are selected randomly over a period of one week. The following are observed:

1384, 683, 1534, 405

Let $\mu$ = population average gallons of wastewater discharged per hour

So, Null Hypothesis, $H_0$ : $\mu \leq$ 500 gallons {means that not more than 500 gallons of wastewater per hour, on the average, is discharged into a neighboring lake}

Alternate Hypothesis, $H_A$ : $\mu$ > 500 gallons {means that more than 500 gallons of wastewater per hour, on the average, is discharged into a neighboring lake}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = $\frac{\sum X}{n}$ = 1001.5 gallons

s = sample standard deviation = $\sqrt{\frac{\sum (X - \bar X)^{2} }{n-1} }$ = 543.79

n = sample of periods = 4

So, the test statistics = $\frac{1001.5-500}{\frac{543.79}{\sqrt{4} } }$ ~ $t_3$

= 1.844

The value of t-test statistics is 1.844.

Since in the question we are not given with the level of significance so we assume it to be 5%. Now, at 0.05 level of significance, the t table gives a critical value of 2.353 at 3 degrees of freedom for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.844 < 2.353, so we have insufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that not more than 500 gallons of wastewater per hour, on average, is discharged into a neighboring lake.

4 0

3 years ago

Find each product (5a^5)(6a^6)=?

Margaret [11]

Multiplying exponents will just have to follow a rule.
Make sure that the base are the same otherwise, you keep it as is.
If they have the same bases, then just add the exponents.

= (5a^5)(6a^6)
= 30a^11

So the final answer is 30a^11.

5 0

3 years ago

PLEASE NEED HELP QUESTION AND ANSWERS IN THE PIC

guajiro [1.7K]

Answer:

B

Step-by-step explanation:

CDE and CBA are similar triangles

Ratio = CE/CA = 24/48 = 1/2

CD/CB = 1/2

18/(24+x) = 1/2

24+x = 36

x = 12

DE/BA = 1/2

y/24 = 1/2

y = 12

6 0

3 years ago

Write an expression to represent 1 less than the quotient of four and a number X​

Write an expression to represent 1 less than the quotient of four and a number X