All categories

3 years ago

Ryan is building a tree he use. It will take hours to complete. He can work on the tree

Mathematics

1 answer:

Anna71 [15]3 years ago

7 0

Answer:

come have IT with me baby

Step-by-step explanation:

it will make us feel better

You might be interested in

The ability to complete math equations, convert measurements, set timers and define words are all done from directly within the

katrin2010 [14]

The term referred to the space provided is Omnibox. This browser address bar allowed to solve math equations, convert measurement, set timers and define words. It is similar to a typical browser such as google chrome and Mozilla firefox. hope this helps

8 0

4 years ago

Read 2 more answers

Please help me<br><br> I don’t understand it

Anna35 [415]

Answer:

Step-by-step explanation:

The solution is B. In each equation, it uses parenthesis to group operations. On the left, each pair repeats one number either 1.6 and 4.2. On the right is written the reduced form by writing the expression with a greatest common factor.

Option A is incorrect since 1.6 is not the GCF which appears in each parenthesis.

Option B is incorrect because the operation in the parenthesis is multiplication and not addition.

Option C is incorrect because 1.6 as a GCF is applied using multiplication.

Option D is correct since 1.6 does occur as a GCF in each parenthesis. It also has written correctly (4.2 +7) since addition is the operation between the parenthesis.

8 0

4 years ago

Find the solution of the system of equations.<br> - 7x – 4y = -44<br> 7x - 3y = 16

lys-0071 [83]

Answer:

{x,y} = {5,8}

Step-by-step explanation:

[1] 7x-3y+5=16

[2] 4y=3x+17

[1] 7x - 3y = 11

[2] -3x + 4y = 17

// Solve equation [2] for the variable y

[2] 4y = 3x + 17

[2] y = 3x/4 + 17/4

// Plug this in for variable y in equation [1]

[1] 7x - 3•(3x/4+17/4) = 11

[1] 19x/4 = 95/4

[1] 19x = 95

// Solve equation [1] for the variable x

[1] 19x = 95

[1] x = 5

// By now we know this much :

x = 5

y = 3x/4+17/4

// Use the x value to solve for y

y = (3/4)(5)+17/4 = 8

6 0

4 years ago

If the integral of the product of x squared and e raised to the negative 4 times x power, dx equals the product of negative 1 ov

Nataly_w [17]

Answer:

$A + B + E = 32$

Step-by-step explanation:

Given

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C$

Required

Find $A +B + E$

We have:

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C$

Using integration by parts

$\int {u} \, dv = uv - \int vdu$

Where

$u = x^2$ and $dv = e^{-4x}dx$

Solve for du (differentiate u)

$du = 2x\ dx$

Solve for v (integrate dv)

$v = -\frac{1}{4}e^{-4x}$

So, we have:

$\int {u} \, dv = uv - \int vdu$

$\int\limits {x^2\cdot e^{-4x}} \, dx = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx$

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx$

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx$

-----------------------------------------------------------------------

Solving

$\int xe^{-4x} dx$

Integration by parts

$u = x$ ---- $du = dx$

$dv = e^{-4x}dx$ ---------- $v = -\frac{1}{4}e^{-4x}$

So:

$\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx$

$\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx$

$\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}$

So, we have:

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx$

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x} -\frac{1}{4}e^{-4x}]$

Open bracket

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x} -\frac{1}{8}e^{-4x}$

Factor out $e^{-4x}$

$\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}$

Rewrite as:

$\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}$

Recall that:

$\int\limits {x^2\cdot e^{-4x}} \, dx = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C$

$\int\limits {x^2\cdot e^{-4x}} \, dx = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}$

By comparison:

$-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2$

$-\frac{1}{8}x = -\frac{1}{64}Bx$

$-\frac{1}{8} = -\frac{1}{64}E$

Solve A, B and C

$-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2$

Divide by $-x^2$

$\frac{1}{4} = \frac{1}{64}A$

Multiply by 64

$64 * \frac{1}{4} = A$

$A =16$

$-\frac{1}{8}x = -\frac{1}{64}Bx$

Divide by $-x$

$\frac{1}{8} = \frac{1}{64}B$

Multiply by 64

$64 * \frac{1}{8} = \frac{1}{64}B*64$

$B = 8$

$-\frac{1}{8} = -\frac{1}{64}E$

Multiply by -64

$-64 * -\frac{1}{8} = -\frac{1}{64}E * -64$

$E = 8$

So:

$A + B + E = 16 +8+8$

$A + B + E = 32$

4 0

3 years ago

Plzzzzz help me simplify

noname [10]

3x2 + 5x

Tell me if u need the work :D

3 0

3 years ago