Given :
An alloy is a mixture of metals. Suppose that a certain alloy is made by mixing 50 g of an alloy containing 12% copper with 78 g of an alloy containing 92% copper.
To Find :
How many grams of copper are in the resulting mixture what percentage of the resulting mixture is copper.
Solution :
Mass of copper in 50 gm alloy = .
Mass of copper in 78 gm alloy = .
Total mass of copper, ( 6 + 76.44 ) gm = 82.44 gram.
Percentage of copper in resulting mixture :
Hence, this is the required solution.
Dime value: $0.10
Nickel value: $0.05
For this word problem, you are asked to create an algebraic expression (an equation) for the unknown variables.
Now, we know that a dime is worth $0.10 or 10 cents and a nickel is worth $0.05 or 5 cents. So, all you would have to do is create an equation that takes those values into account.
5n + 10d
Your algebraic expression would be B. 5n + 10d
I hope this helps!
Answer:
x = 3.51
Step-by-step explanation:
Since, formula to determine the area f a triangle is,
Area =
8 =
16 = x(3x - 7) + 1(3x - 7)
16 = 3x² - 7x + 3x - 7
16 = 3x² - 4x - 7
0 = 3x² - 4x - 23
3x²- 4x - 23 = 0
By quadratic formula,
x =
x =
x =
x =
x = 3.51, -2.18
But the length of sides can't be negative.
Therefore, x = 3.51 will be the answer.
The square root of 5 is 2.23 so it would be closer to 2
Answer: −2.4f − 22
Step-by-step explanation: simply combine like terms. -2.7f + .3f would be -2.4f, and -14 - 8 is -22.