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Dima020 [189]
2 years ago
10

PLZ HELP ME WILL MARK BRAINLIST AND 50 points IF THE ANSWER IS CORRECT!!!

Mathematics
1 answer:
never [62]2 years ago
5 0

Answer for the question:

It is B.

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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621​
REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

a=-6

T_n=58

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

\therefore d=a_2-a_1=-5-(-6)=-5+6=1

Now we use the formula of A.P.

T_n=a+(n-1)d

On substituting the values, we get;

58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65

So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

Now we use the formula of Sum of n_terms.

S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0
3 years ago
The product of a number w and 73
wolverine [178]
W times 73 because product means multiply
3 0
3 years ago
Use the zero product property to find the solutions to the equation x2 – 15x – 100 = 0.
IrinaK [193]

Answer:

x= 20      x =-5

Step-by-step explanation:

x^2 – 15x – 100 = 0.

What two numbers multiply to -100 and add to -15

-20 * 5 = -100

-20 +5 = -15

(x-20) (x+5) =0

Using the zero product property

x-20 =0     x+5 = 0

x= 20      x =-5

7 0
3 years ago
Read 2 more answers
FREEE POINTSSS!!!!!! x + 6 = -11
katrin2010 [14]

Answer:

x = -11 - 6 = -17

4 0
3 years ago
Read 2 more answers
Prove that the sum of all natural numbers is -1/12.
ankoles [38]
This is not true. The infinite series


\displaystyle\sum_{n=1}^\infty n

converges if and only if the sequence of its partial sums converges. The k-th partial sum is

\displaystyle\sum_{n=1}^kn=\frac{k(k+1)}2

but clearly this diverges as k gets arbitrarily large.
5 0
3 years ago
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