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2 years ago

PLZ HELP ME WILL MARK BRAINLIST AND 50 points IF THE ANSWER IS CORRECT!!!

Mathematics

1 answer:

never [62]2 years ago

5 0

Answer for the question:

It is B.

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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0

3 years ago

The product of a number w and 73

wolverine [178]

W times 73 because product means multiply

3 0

3 years ago

Use the zero product property to find the solutions to the equation x2 – 15x – 100 = 0.

IrinaK [193]

Answer:

x= 20 x =-5

Step-by-step explanation:

x^2 – 15x – 100 = 0.

What two numbers multiply to -100 and add to -15

-20 * 5 = -100

-20 +5 = -15

(x-20) (x+5) =0

Using the zero product property

x-20 =0 x+5 = 0

x= 20 x =-5

7 0

3 years ago

Read 2 more answers

FREEE POINTSSS!!!!!! x + 6 = -11

katrin2010 [14]

Answer:

x = -11 - 6 = -17

4 0

3 years ago

Read 2 more answers

Prove that the sum of all natural numbers is -1/12.

ankoles [38]

This is not true. The infinite series

$\displaystyle\sum_{n=1}^\infty n$

converges if and only if the sequence of its partial sums converges. The $k$ -th partial sum is

$\displaystyle\sum_{n=1}^kn=\frac{k(k+1)}2$

but clearly this diverges as $k$ gets arbitrarily large.

5 0

3 years ago