A×4 = E, so A = E/4
B/4 = E, so B = 4E
C+4 = E, so C = E=4
D-4 = E, so D = E+4
and
A+B+C+D=100.
now substitute the values that we got of A, B, C and D in the equation, to get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
E = 16
i answered same question before too ....
<span>Hope it helps !!!</span>
That's a <em>rhombus</em>. If it has one interior right angle, then
it's a special case of rhombus known as a "square".
Step-by-step explanation:
Ok, so from previous question
(x-h)^2=4p(y-k)
distance from focus to directix is 2
2/2=1=p
1>-1
focus is above the vertex
1 unit down from (0,1) is (0,0)
vertex at (0,0)
since focus is above, p is positive
(x-0)^2=4(1)(y-0)
x^2=4y
4y=x^2
divide both sides by 4
y=(1/4)x^2
f(x)=1/4x^2
2nd one is answer
