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2 years ago

How far is 10 kilometers(km) in miles(mi)? Use: 1mi = 1.6km can someone help me pleaseee

Mathematics

2 answers:

Sedbober [7]2 years ago

7 0

Answer:

6.25

Step-by-step explanation:

10 divided by 1.6= 6.25 Hope this helps! Have a good day! :)

Alik [6]2 years ago

6 0

Answer:

$\huge\boxed{\sf 10\ km = 6.25\ miles}$

Step-by-step explanation:

We can use the unitary method to solve this question.

1.6 km = 1 mile

So,

1 km = 1 / 1.6 mile

<em>Multiply both sides by 10</em>

10 km = 1 / 1.6 * 10 miles

10 km = 10 / 1.6 miles

10 km = 6.25 miles

$\rule[225]{225}{2}$

Hope this helped!

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Answer: Carlos is correct

Step-by-step explanation:

2x^5-250x^2

The first step is to factorize out 2x^2

2x^2(x^3-125)

This can be rewritten as

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Recall, difference if cube (a^3-b^3)

= (a-b)(a^2 +ab + b^2)

from our equation,

a= x

b = 5.

So the difference of cubes will be

2x^2[(x-5) (x^2 + 5x + 5^2)]

=2x^2[(x-5) (x^2 + 5x + 25)]

Carlos followed these steps. So he is correct. Carlos is correct because he correctly factored the GCF, identified a and b, and applied the difference of cubes method.

Amber is incorrect because 125 is equal to b3, not b.

Bernie is incorrect because x2 is not the GCF of the polynomial. The GCF is 2x^2.

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3 years ago

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Step-by-step explanation

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2 years ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). A construction

charle [14.2K]

Answer:

$y=\frac{11}{20}x+6$

Step-by-step explanation:

Given:

Two points are given

x = number of minutes

y = length of the lin

$(x_{1},y_{1} )$ ⇒ (0, 6)

$(x_{2},y_{2} )$ ⇒ (20, 17)

We need to find the equation that represents the relationship between x, y.

Solution:

Using slope formula to find the slope of the equation of the line.

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$m=\frac{17-6}{20-0}\\m=\frac{11}{20}$

So, slope of the line $m = \frac{11}{20}$

Using point slope formula.

$(y-y_{1})=m(x-x_{1})$ ------------(1)

Where, m = slope of the line

Substitute $(x_{1},y_{1} )$ ⇒ (0, 6) and $m = \frac{11}{20}$ in equation 1.

$(y-6)=\frac{11}{20} (x-0)$

$y-6=\frac{11}{20}x$

Add 6 both side of the equation.

$y-6+6=\frac{11}{20}x+6$

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Therefore, the equation that represents the relationship between x and y is written as:

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3 years ago

(-6,1) is a point on the graph of y=g(x)

NNADVOKAT [17]

Answer:

$(-7, -4)$

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Step-by-step explanation:

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subtract two units from the input variable (x), multiply the output variable (y) by -2 and then add 4 units

So the point in the graph of $y = -2g(x -2) +4$ is

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The point is: $(-4, 2)$

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So the point in the graph of $y=g(2x+2)$ is

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