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3 years ago

An animal shelter provides a bowl with 1.45 liters of water for 3 cats.

Mathematics

1 answer:

Kay [80]3 years ago

4 0

Answer:

n animal shelter provides a bowl with 1.45 liters of water for 3 cats.

About how much water will be left after the cats drink their average daily amount of water?

Canada Goose 0.24

Cat 0.15

Mink 0.10

Opossum 0.30

Bald Eagle 0.16

Step-by-step explanation:

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F(x) = 4* How to evaluate

photoshop1234 [79]

Answer:fx=4

Step-by-step explanation:

fx=4

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3 years ago

Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period 2 is 9

Forecast can be given by

$F_{t+1}=F_t+\alpha (D_t-F_t)$

where

$F_{t+1}=Future Forecast$

$F_t=Present\ Period\ Forecast$

$D_t=Present\ Period\ Demand$

$\alpha =smoothing\ constant$

$F_{t+1}=5+0.2(7-5)$

$F_{t+1}=5.4$

Forecast for Period 3

$F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})$

$F_{t+2}=5.4+0.2\cdot (9-5.4)$

$F_{t+2}=6.12$

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3 years ago

Give the difference of 8/13 and 5/13 A. 3/13 B. 8/13 C. 5/13

nikitadnepr [17]

Answer:

3/13

Step-by-step explanation:

8/13 subtract by 5/13. If the denominator is the same, you keep it, don't change it. Just subtract the numerator.

Make sure to simplify, if it is already simplified that will be the answer.

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2 years ago

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The chart shows a combined supply and demand schedule.

Readme [11.4K]

Answer:

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Step-by-step explanation:

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3 years ago

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A ball is thrown upward from the top of a building. The function below shows the height of the ball in relation to sea level, f(

Marina86 [1]

$f(t) = -16t^{2} +48t + 100$
Average rate of change from t = 3 seconds to t = 5 seconds = $\frac{f(5)-f(3)}{5-3} = \frac{(-16( 5^{2})+48(5)+100)-(-16( 3^{2})+48(3)+100 }{2}=$ $\frac{(-16(25)+240+100)-(-16(9)+144+100)}{2} = \frac{(-400+240+100)-(-144+144+100)}{2}=$ $\frac{-60-100}{2} = \frac{-160}{2} = -80$

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3 years ago