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3 years ago

An animal shelter provides a bowl with 1.45 liters of water for 3 cats.

Mathematics

1 answer:

Kay [80]3 years ago

4 0

Answer:

n animal shelter provides a bowl with 1.45 liters of water for 3 cats.

About how much water will be left after the cats drink their average daily amount of water?

Canada Goose 0.24

Cat 0.15

Mink 0.10

Opossum 0.30

Bald Eagle 0.16

Step-by-step explanation:

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Which of the following diagram represent a relation that is not a function

andrew11 [14]

You didn’t even post a diagram

which of the following diagram represent a relation that is not a function

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3 years ago

The radius of the large sphere is times longer than the radius of the small sphere.

jeka94

Answer:

1/3

Step-by-step explanation:

You can try it I keep getting 3 so maybe that’s the answer

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3 years ago

Read 2 more answers

Convert 3.25 to a fraction

Lunna [17]

3 and one 1/4 or 13/4

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3 years ago

A scientist needs to make 2 liters of saline solution (salt water), in which the salt level must be at 15% concentration (meanin

slamgirl [31]

Answer:

We need 1.6 liters of the 10 % concentration level and saline solution and 0.4 liters of the 35 % concentration level and saline solution.

Step-by-step explanation:

Let V₁ be the volume of the 10% concentration saline solution required and V₂ be the volume of 35% concentration saline solution required.

Since mass = concentration × volume, the total mass of the 10% and 35% volume saline solution equal the mass of the 2 liter 15% volume solution.

So, 0.1V₁ + 0.35V₂ = 2 × 0.15

0.1V₁ + 0.35V₂ = 0.3 (1)

Also, the total volume of the 15 % solution must equal 2 liters. So,

V₁ + V₂ = 2 (2)

V₁ = 2 - V₂ (3)

putting equation (3) into equation (1), we have

0.1(2 - V₂) + 0.35V₂ = 0.3

0.2 - 0.1V₂ + 0.35V₂ = 0.3

we now collect terms, so

- 0.1V₂ + 0.35V₂ = 0.3 - 0.2

0.25V₂ = 0.1

we now divide through by 0.25, so

V₂ = 0.1/0.25

V₂ = 0.4 liters

we now put V₂ into (3), we have,

V₁ = 2 - 0.4

V₁ = 1.6 liters

So, we need 1.6 liters of the 10 % concentration level and saline solution and 0.4 liters of the 35 % concentration level and saline solution.

3 0

3 years ago

An arc measures 50°in a circle with a radius of 8 cm. What is the area of the sector to the nearest tenth of a square centimeter

marysya [2.9K]

Answer:

$27.9cm^2$

Step-by-step explanation:

The <u>total area</u> of the circle is given by:

$a=\pi r^2$

where $\pi$ is a constant $\pi=3.1416$

and $r$ is the radius: $r=8cm$

Thus the total area of this circle is:

$a=(3.1416)(8cm)^2\\a=(3.1416)(64cm^2)\\a=201.06cm^2$

We want only the area of the arc that measures 50°. For this we must remember that the arc of the total circle is 360°.

Thus, we want 50° out of the 360° degrees in the circle. For this, we divide the total area by 360 and then we multiply by 50:

$\frac{201.06cm^2}{360}(50)=0.5585cm^2(50)=27.9cm^2$

the area of the sector to the nearest tenth is $27.9cm^2$

3 0

3 years ago