1) √3 √7 = √21
2) √5 √245 = √5 √5 * 49 = √5 * 7√5 = 7 √5 * 5 = 7 √25 = 7 * 5 = 35
3) √77 ÷ √11 = as is. can't be simplified.
4) (√59)² = 59 ; the square root was cancelled by squared.
5) 3√6 x 8√7 = 3 * 8 √6 * 7 = 24 √42
6) 5√3 x 6 √3 = 5 * 6 √3 * 3 = 30 √9 = 30 * 3 = 90
7) 40√30 ÷ 5√3 = (40 / 5) * (√30 /√3) = 8 * ((√3 *10) / √3) = 8 √10
8) (6√5)² = 6² * √5² = 36 * 5 = 180
Answer:
After finding the money we were short with, we find that Option-b, that is, $2200 is the correct option.
Step-by-step explanation:
Given that the cost to repair the damaged car is $2700. We have $500.
Insurance company is a company that gives the payment of someone's valuable items when they are lost or get damaged. For example, home insurance, car insurance, life insurance and much more.
Here we can see that we are short with $2700 - $500 = $2200.
So, to complete the payment, insurance company will pay $2200.
Clearly, the correct option is Option-b.
For more explanation, refer the following link:
brainly.com/question/33585
#SPJ10
Answer:
4:18 pm
Step-by-step explanation:
An airport offers 2 shuttles that run on different schedules.If both shuttles leave the airport at 4:00 p.m.,at what time will they next leave theairport together.
Shuttle A leaves every 6 minutes
Shuttle B leaves every 9 minutes
Solution
To solve for when next both shuttles will leave the airport together, find the least common multiples of 6 minutes and 9 minutes
Shuttle A (every 6 minutes) = 6, 12, 18, 24
Shuttle B (every 9 minutes) = 9, 18, 27, 36
The least common multiples of 6 minutes and 9 minutes is 18 minutes
4:00 pm + 18 minutes
= 4:18 pm
The next time both shuttles will leave theairport together is 4:18 pm of the same day
Kevin is 6-7 years old as 6.2222222222 x 9 is 56
