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3 years ago

Divide: (x2 – 3x – 33) = (x + 4)

Mathematics

2 answers:

Simora [160]3 years ago

8 0

Answer:

$\rm (x^2 - 3x - 33)\div(x + 4) = x - 7 - \dfrac{5}{x + 4}$

Step-by-step explanation:

$\rm\qquad\quad\quad{x-7}\\ \begin{array}{cc} \cline{2 - 2}\rm x + 4 )&\rm \ x^2 - 3x -33\\&\rm x^2 + 4x \\ \cline{2-2}& \rm \ \ \ \ -7x-33\\ &\sf \ - 7x-28 \\ \cline{2-2} & \rm \ \ -5 \\ \cline{2-2} \end{array}$

Quotient → x - 7

Remainder → -5

Divisor → x + 4

katovenus [111]3 years ago

7 0

Answer:

x-7-5/x+4

So answer C

Step-by-step explanation:

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2 years ago

Suppose that y varies inversely with x. Use the information to find k, and then choose the equation of variation. x = 2 when y =

Sergeeva-Olga [200]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Claire Judice

Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

Step-by-step explanation:

Given:

The equation to solve is given as:

$5x^5+6x^4+80x^3+96x^2=0$

Factoring $x^2$ from all the terms, we get:

$x^2(5x^3+6x^2+80x+96)=0$

Now, rearranging the terms, we get:

$x^2(5x^3+80x+6x^2+96)=0$

Now, factoring $5x$ from the first two terms and 6 from the last two terms, we get:

$x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0$

Now, equating each factor to 0 and solving for 'x', we get:

$x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i$

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

4 0

3 years ago