Answer:
the answer to this complicated problem is 25
Distance of each track are:
D₁ = 428.5 yd
D₂ = 436.35 yd
D₃ = 444.20 yd
D₄ = 452.05 yd
D₅ = 459.91 yd
D₆ = 467.76 yd
D₇ = 475.61 yd
D₈ = 483.47 yd
<u>Explanation:</u>
Given:
Track is divided into 8 lanes.
The length around each track is the two lengths of the rectangle plus the two lengths of the semi-circle with varying diameters.
Thus,

Starting from the innermost edge with a diameter of 60yd.
Each lane is 10/8 = 1.25yd
So, the diameter increases by 2(1.25) = 2.5 yd each lane going outward.
So, the distances are:
D₁ = 240 + π (60) → 428.5yd
D₂ = 240 + π(60 + 2.5) → 436.35 yd
D₃ = 240 + π(60 + 5) → 444.20 yd
D₄ = 240 + π(60 + 7.5) → 452.05 yd
D₅ = 240 + π(60 + 10) → 459.91 yd
D₆ = 24 + π(60 + 12.5) → 467.76 yd
D₇ = 240 + π(60 + 15) → 475.61 yd
D₈ = 240 + π(60 + 17.5) → 483.47 yd
Answer:
-45
Step-by-step explanation:
The question is asking for the sum of the sequence. Therefore, there is no such thing as a "radians" answer.
When you evaluate the sum, you should get -45 as your answer. To find so, you simply plug in 1 as <em>n</em> and other numbers then add the result.
Answer:
See answers below
Step-by-step explanation:
Perimeter of a square = 4L
L sis the side length of the square
L = 5x^4y^2
perimeter = 4(5x^4y^2)
perimeter = 20x^4y^2
2) Length = 6x-10
Width = 4x+3
Area of rectangle = Length * Width
Area of rectangle = (6x-10)(4x+3)
Area of rectangle = 24x^2+18x-40x-30
Area of rectangle= 24x^2-22x-30
perimeter = 2(L+W)
perimeter 2(6x-10+4x+3)
perimeter = 2(10x-7)
perimeter = 20x-14
Hence the perimeter of the rectangle is 20x-14