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Andreas93 [3]
3 years ago
9

Find the length of PR

Mathematics
2 answers:
svetlana [45]3 years ago
5 0

Answer:

4(2x+1)

Step-by-step explanation:

Add the expressions 3x-2 and 5x+6

which is 8x+4

since every one of the answers are in distributive form, just take the GCF (Greatest Common Factor) out of both

Tatiana [17]3 years ago
5 0
4(2x + 1)....................
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Which equation represents the line that passes through the point (1,5) with a slope of-2
svlad2 [7]

Answer:

The equation of the line would be y = -2x + 7

Step-by-step explanation:

In order to solve this, use the point and the slope in point-slope form. Then solve for y.

y - y1 = m(x - x1)

y - 5 = -2(x - 1)

y - 5 = -2x + 2

y = -2x + 7

3 0
3 years ago
I thought of a number. This number double is 7 less than 29. What is my number? hurry please
jekas [21]

Answer:

11

Step-by-step explanation:

11*2=22

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6 0
2 years ago
Read 2 more answers
(a2 − 6) and (a2 + 4) are the factors of
sleet_krkn [62]
(a²-6)(a²-4) simplify

a⁴-4a²-6a²+24

Combine like terms

a⁴-10a²+24
8 0
3 years ago
Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh
fredd [130]

With

\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k

we have

\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

The vector field evaluated over this parameterization is

\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k

so the line integral is

\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4

6 0
3 years ago
Two number cubes are rolled and the product of the two numbers shown is calculated. Calculate P(multiple of 6). Record your answ
Ludmilka [50]

Answer:

1/6

Step-by-step explanation:

5 0
3 years ago
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