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V125BC [204]
3 years ago
14

Question 13 REASONING Write a function g(x) to represent the translated graph. f(x) = 3x + 7 translated 4 units up.​

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
7 0
Answer: g(x) = 3x + 11
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PLEASE HELP FAST! UNIT TEST and I NEED A GOOD GRADE.
Crank

Slope = -5

y-intercept = 5

y = -5x + 5

Hope this helps! ;)

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A bag contains three red marbles and two blue marbles. Marcus reaches in and pulls out a marble, replaces it, but then reaches i
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your answer would be \frac{1}{5}

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Jim and Sean went to the diner and bought two egg scrambles. Jim also got a cup of coffee for a dollar. If their total bill was
Alex73 [517]

Answer:

If only Jim purchased a cup of coffee, we will subtract its cost from the total;

9.50 - 1.00 = 8.50

Assuming that the two purchased nothing else for breakfast, and that the cost of an egg scramble was the same for both, let's call the price of the egg scramble x.

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3 years ago
Can someone please help​
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Answer: y= -x +4

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3 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
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