Solve for x mathematics

Mr. Herman's class is selling candy for a school fundraiser. The class has a goal of raising $500dollar sign by selling c box of

hoa [83]

Answer:

$500. 500/2.75= 181 boxes

Step-by-step explanation:

You divide the amount of money by the amonunt of money for each box to find how many boxes you sell to make.

8 0

3 years ago

Read 2 more answers

Someone ask me to solve this.

Semenov [28]

X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 -----> 3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

3k +4h =4 ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4 or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4 , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .

6 0

3 years ago

Anna earns $9 an hour babysitting. She wants to buy a 16 GB iPad that is $120. Anna has saved $45 so far. How many more hours of

natta225 [31]

Its 8.33 but go ahead and put 9

8 0

3 years ago

Read 2 more answers

Explain the Error: Jayme tells her friend that ordered pairs that have an x-coordinate of O lie on the x-axis. She uses the orig

Paul [167]

Answer:

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Step-by-step explanation:

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4 0

3 years ago

Pollution Rates Assignment

stepan [7]

Answer:

1. a) 4.8 lb

I) 8%

II) 0.384 lb

2. a) 12.5 lb

I) 8%

II) 1 lb

Step-by-step explanation:

Let's begin by listing out the given variables:

mass of pesticide (m) = 12 lb,

40WP (40 weight percent) means the active ingredient comprises 40% of the total mass of the pesticide

a) amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 12 * 40% = 12 * 0.4

x = 4.8 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 4.8 * 8% = 4.8 * 0.08

z = 0.384 lb

2. Let's list out the variables given, we have:

mass of pesticide = 25 lb, weight percent of active ingredient = 50% = 0.5

amount of active ingredient = mass of the pesticide * weight percentage of the active ingredient

x = 25 * 0.5

x = 12.5 lb

I. If the soil has an absorption rate of 92%, that means 8% will go into the run-off

The percentage of active ingredient that will end up in the run-off = the percentage of the active ingredient (100%) - the absorption rate

y = (100 - 92)%

y = 8%

II. amount of of active ingredient that will end up in the run-off = amount of active ingredient * the percentage of active ingredient that will end up in the run-off

z = x * y = 12.5 * 8% = 12.5 * 0.08

z = 1 lb

7 0

3 years ago