3 years ago

What is first coordinite

Mathematics

1 answer:

finlep [7]3 years ago

5 0

Answer:

with the information you have given, the first coordinate is this:

Step-by-step explanation:

A first coordinate is on a graph, and it is the first dot, or coordinate set on the plane.

~Ren

You might be interested in

F(x) = x^2 – (x + 3), what is the value of f(8)

eimsori [14]

Answer:

Step-by-step explanation:

f(x) = x^2 – (x + 3)

Let x = 8

f(8) = 8^2 – (8 + 3)

=64 - (11)

=53

8 0

3 years ago

Tito walked threemore miles then Daniel. if Daniel walked 2 miles how far did Tito walk?

marusya05 [52]

5 miles because 2 miles then add 3 miles equals 5 miles

4 0

3 years ago

Read 2 more answers

Plz help ill give u brainlyest. <br><br> Also anser a and b

erica [24]

Answer:

A) 4/7 feet

B) 4/7 x 15 = 60/7 or $8\frac{4}{7}$

5 0

3 years ago

Which formula describes the following geometric sequence? Remember that n represents the term number.

anzhelika [568]

The formula on nth term is l=ar^(n-1)
The 1st term is 2 & r,the ration =3

Then is 2x3^(n-1). Mind you (n-1) is an exponent on 3

3 0

3 years ago

Read 2 more answers

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago