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pantera1 [17]
3 years ago
15

The coordinates of AABC are A(0,0), B(7,0), and C(1,5). Triangle A'B'C'is the image of AABC rotated counterclockwise about the o

rigin. What was the angle of rotation?​
Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

i dont know

Step-by-step explanation:

that is too hard

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Determine the scale factor for each pair of triangles
Alik [6]

Triangle A is the original triangle, and triangle A' is the image.

We need a pair of corresponding sides in the two triangles that are both labeled with lengths.

We see the side labeled 15.2 mm in triangle A', and we see the side labeled 3.8 mm in triangle A. These two sides are corresponding sides.

Divide the length of the side in the image by the length of the side in the original to find the scale factor.

(15.2 mm)/(3.8 mm) = 4

The scale factor is 4.

6 0
3 years ago
The dimensions of a triangular prism are shown in the diagram. What is the
goldfiish [28.3K]

Answer:

D

Step-by-step explanation:

SA = bh + (s1 + s2 + s3)H is the formula to find out the surface area

b is base, h is height (small height), s's are the sides, H is the height (longer one)

SA = 12(9) + (10 + 10 + 12)32

SA = 108 + (32)32

SA = 108 + 1024

SA = 1132

5 0
3 years ago
Read 2 more answers
Claire and Malia are training for a race A)Claire runs 10 km in 1 hour. How many kilometers does she run in half an hour? In 2 1
andrey2020 [161]

Answer:

A) 5km, 25km    B) 2.5km, 12.5km

Step-by-step explanation:

A)Claire runs 10 km in 1 hour.

she runs 10/2=5km in 1/2 hour.

in 2 1/2, she runs 10*2 1/2=25km


B)Malia runs 5 miles in 1 hour.

she runs 5/2=2 1/2km in 1/2 hour.

in 2 1/2, she runs 5*2 1/2=12 1/2km

4 0
4 years ago
Read 2 more answers
How do you Convert 5 to qn improper Fraction?
dybincka [34]
I’m assuming you mean the whole number 5.

5/1 is an improper fraction of 5. You can also use 10/2 or 15/3.
4 0
3 years ago
Read 2 more answers
Find the remainder when f(x) is divided by (x - k).
rusak2 [61]
Synthetic division:

3   |   3   11    2      -7      61
.    |         9   60   186    537
- - - - - - - - - - - - - - - - - - - -
.    |   3   20  62   179    598

which translates to

\dfrac{3x^4+11x^3+2x^2-7x+61}{x-3}=3x^3+20x^2+62x+179+\dfrac{598}{x-3}

i.e. you're left with a remainder of 598.
6 0
3 years ago
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