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pashok25 [27]
3 years ago
14

50 POINTS! , PLEASE HELP ME MATH PEOPLE.

Mathematics
1 answer:
In-s [12.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

Rank b

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Choose the fraction that has not been reduced to simplest form.
Thepotemich [5.8K]
first one since it’s 1/16 simplest form or 11/17 cuz it’s obv
8 0
3 years ago
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An olympic sprinter can run 56 yards in 8 seconds. At the same rate, how long (in seconds) would it take the sprinter to run 81
aniked [119]

Answer:

20,365.7 seconds

Step-by-step explanation:

First, we need to know how to convert yards to miles, as the question is in miles. We know that 1 mile is equivalent to 1760 yards. So we have:

1 mi = 1760 yards

If we multiply both sides by 81:

81 mi = 142,560‬ yards

And we know that the sprinter needs 8 second to run 56 yards:

8 s = 56 yards

If we divide both sides by 56 we get the time he needs for 1 yard:

8/56 s = 56/56 yards

1/7 s = 1 yard

So, takes him 1/7 seconds to run one yard. At this rate he runs 142,560 yards in:

(1/7) * 142,560 = 20,365.7

So, he needs 20,365.7 seconds to run 81 miles (142,560 yards)

6 0
4 years ago
Marking Brainliest ! Answer quickly
Alex

Answer:

5/7

Step-by-step explanation:

20/28=5/7

Hoped i answered u

4 0
3 years ago
Read 2 more answers
Can you hep me with this question...
Harman [31]

Answer:

so like I just looked it up so try

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----

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3 0
3 years ago
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50 POINTS!!!
Goryan [66]

9514 1404 393

Answer:

  • f(x) = x
  • g(x) = -2x+1
  • f(x) -(-g(x)) = -x+1
  • f(x) +g(x) = -x+1
  • f(x)-(-g(x)) = (f+g)(x) is true for all functions f and g, linear or not

Step-by-step explanation:

We can define a couple of linear functions as ...

  f(x) = x

  g(x) = -2x+1

Then the reflected function -g(x) is ...

  -g(x) = -(-2x +1) = 2x -1

And the difference from f(x) is ...

  f(x) -(-g(x)) = x -(2x -1) = -x +1 . . . . f(x) -(-g(x))

We want to compare that to the sum of the functions:

  f(x) +g(x) = x +(-2x +1) = -x +1 . . . . f(x) +g(x)

The two versions of the function expression have the same value.

These results are <em>a property of addition</em>, so do not depend on the nature of f(x) or g(x). They will hold for every function.

3 0
3 years ago
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