Answer:
The reduced form of cytochrome c more likely to give up its electron to oxidized cytochrome a having a higher reduction potential.
Explanation:
Electrons from NADH and FADH2 flow spontaneously from one electron carrier of the electron transport chain to the other. This occurs since the proteins of the ETC are present in the order of increasing reduction potential. The reduced cytochrome b has lower reduction potential than cytochrome c1 which in turn has a lower reduction potential than the cytochrome c.
Cytochrome c is a soluble protein and its single heme accepts an electron from cytochrome b of the Complex III. Now, cytochrome c moves to complex IV which has higher reduction potential and donates the electron to cytochrome a which in turn passes the electrons to O2 via cytochrome a3.
A female fox is called a vixen
Hey there!
Your answer: Available Space
The question is asking, which of the following options would be a (limited source). We have to find a option that has a limited source, which means that there is a limit to something. Your answer is (b) because there are limited space with the spce that is already available. Air temperature would NOT be your answer.
Answer:
D. The first division will reduce the number of chromosomes by half for each daughter cell, and the second division will move single chromatids to each daughter cell.
Explanation:
Gametes are formed by meiosis in diploid gamete mother cells. During gamete formation, the gamete mother cell in the yeast would undergo meiosis I. During first division (meiosis-I), the process of crossing over during prophase-I creates genetic variations and movement of homologous chromosomes to the opposite poles during anaphase-I reduces the chromosome number to half in each daughter cell.
Two daughter cells are formed by the end of meiosis-I each of which enters meiosis-II. Splitting of centromere and separation of sister chromatids during anaphase-II of meiosis-II results in the movement of single chromatids to the opposite poles of the cells.
