Basically, we need to find the diagonal of the square. Once we have the diagonal, we need to find if it's more or less than 11 cm, which is diameter of the circle.
This is the formula we'll use:
a²+b²=c²
Since it's a square, a and b are the same.
7²+7²=c²
49+49=c²
98=c²
√98=c
c=9.8995
So, the diagonal is 9.8995
9.8995<11
So, since the diagonal of the square is 9.8995 cm, it is less than the circumference of the circle meaning that it will fit in to the circle without touch the circle's circumference.
Answer:
156 
Step-by-step explanation:
find the areas of all the faces and add them up
area of a rectangle: 
area of a trapezoid: 
the area of the trapezoid is multiplied by 2 because there's a top and bottom
<span>(2p + q) ( –3q – 6p + 1)
= -6pq - 12p^2 + 2p - 3q^2 - 6pq + q
= -12p^2 -12pq +2p -3q^2 + q
so answer is b. </span> -12p^2 -12pq +2p -3q^2 + q
