Answer:
74.4
Step-by-step explanation:
It is already rounded to the nearest tenth of a percent. If it was rounded to the nearest percent it'd be 74%.
<h2>
Answer:</h2>
<h2>
Step-by-step Explanation;</h2>
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<h2>HOPE IT HELPS!!!</h2>
<h2>I NEED BRAINLIEST ✌️</h2>
You haven't told me what the question is. But I put the mouse
to my forehead, closed my eyes, took a deep breath, and I could
see it shimmering in my mind's eye. It was quite fuzzy, but I think
the question is
"What score does Andrew need on the next test
in order to raise his average to 72% ?"
The whole experience drew an incredible amount of energy
out of me, and the mouse is a total wreck. So we'll just go ahead
and answer that one. I hope it's the correct question.
The average score on 4 tests is
(1/4) (the sum of all the scores) .
In order for Andrew to have a 72% average on 4 tests,
the sum of the 4 scores must be
(4) x (72%) = 288% .
Out of that total that he needs, he already has
(64% + 69% + 73%) = 206%
on the first three tests.
So in order to average 72% for all 4 tests,
he'll need to score
(288% - 206%) = 82%
on the fourth one.
Answer:
C. There are the same number of scores in Section and Section
Step-by-step explanation:
The median of section I is greater than the median of section L. Median is the middle value or midpoint in the data set. In the given quiz the data set has different numbers for every section and therefore the values are not same. The data set has 75% of scores in section il which is higher than the section L.
1) 9m
2) 1/64
3) 50d^3
4) pq^2 (p-q) (p-q)
= pq^2 ( p^2 - 9p -9p +18)
= pq^4 - 18p^2q^2 + 8pq^2
= q^2 - 18p + 8
