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polet [3.4K]
3 years ago
5

Tran checked the time on his watch after he finished his daily run select the time that Tran finished running mark all that appl

y
Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

(a) and (b) are correct

Step-by-step explanation:

Given

See attachment for complete question

Required

Select the correct options

A clock is divided into two equal parts.

(1) 1 - 6

(2) 7 - 12

<em>When the hour hand is on (1), then the time is "after"</em>

<em>When the hour hand is on (2), then the time is "before"</em>

<em />

From the attached clock, we have:

(1) The hour hand on 9

(2) The minute hand 1 unit above 9 i.e. 46 minutes

(1) implies that, the time is before 9 i.e. past 8

(2) implies that the minutes is (60 - 46) before 9 or 46 minutes after 8

In (1) and (2) above, we have two interpretations.

1: (60 - 46) minutes before 9

This gives:

14 minutes before 9

2: 46 minutes past 8

i.e. 8 : 46

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-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, \frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }

⇒\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }

⇒\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}

⇒\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}

⇒(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

⇒ (x-2)(x-6) =0 or, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

If, (x-2)(x-6) =0, then x=2 or x=6

If, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0, then x^{2} -5x-2=4

and (x-6)(x+1) =0

Therefore, x=6 or -1

So the solutions for x are -1, 2 6. (Answer)

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0, -5

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