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Kazeer [188]
3 years ago
5

40 POINTS PLEASE HELP ASAP!!! Solve the equation.

Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:the answer is x = -12

Step-by-step explanation:

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What is the equation in slope-intercept form for the line that passes through the points
Tju [1.3M]

Answer:

check the file to see the answer i added a screen shot of the answer

Step-by-step explanation:

8 0
3 years ago
Suppose j varies jointly with g and v, j=1 when g=6 and v=3. Find j when g=8 and v=11
Lady bird [3.3K]

j=4.88 when g=8 and v=11

Further explanation:

When the increase/decrease in one quantity cause increase/decrease in other quantity, it is called direct variation.

Variation is always accompanied by a variation constant.

<u>Given</u>

g and v vary directly with j

IT can be written as:

j∝gv

Putting the variation constant k

j = kgv

Putting g = 6 and v=3

j = kgv\\1 = k * 6 * 3\\1 = 18k\\k = \frac{1}{18}

So the value of k is 1/18 which makes the equation

j = \frac{1}{18}gv\\ Putting\ g=8\ and\ v=11\\j = \frac{1}{18} * 8 * 11\\j = \frac{88}{18}\\ j =4.88

So, j=4.88 when g=8 and v=11

Keywords: Variation, Direct Variation

Learn more about variation at:

  • brainly.com/question/11258952
  • brainly.com/question/1284310

#LearnwithBrainly

8 0
3 years ago
An influenza outbreak occurred in a private high school dormitory that housed 83 students. Case A began on October 1 and cases B
statuscvo [17]

Answer:

The secondary attack rate is 55%

Step-by-step explanation:

Total number of students = 83

Primary cases: cases A+B+C = 3 primary cases.

Secondary cases = 44

Total cases = 44 + 3 = 47

To find the secondary attack rate, we are to assume that the primary cases are now immune because they had the illness.

We have:

Secondary attack rate = \frac{total cases - primary cases}{number of susceptible - primary cases} * 100

= \frac{47-3}{83-3} * 100

= \frac{44}{80} * 100 = 55

The secondary attack rate is 55%

8 0
3 years ago
An element with mass 210 grams decays by 8.3% per minute. How much of the element is remaining after 15 minutes, to the nearest
alexandr1967 [171]

Answer:

57.2 g

Step-by-step explanation:

0 0
4 years ago
I need help with 1-3 i don’t understand that problems and its already over due
Nina [5.8K]

Step-by-step explanation:

For a quadratic equation y = ax² + bx + c, the vertex (the maximum or minimum point) is at x = -b/(2a).

1) y = -0.5t² + 2t + 38

The maximum is at:

t = -2 / (2 × -0.5)

t = 2

The maximum height is:

y = -0.5(2)² + 2(2) + 38

y = 40

The coordinates of the vertex are (2, 40).  That means the missile reaches a maximum height of 40 km after 2 minutes.

2) y = -4.9t² + 12t + 1.6

The maximum is at:

t = -12 / (2 × -4.9)

t = 1.22

The maximum height is:

y = -4.9(1.22)² + 12(1.22) + 1.6

y = 8.95

The coordinates of the vertex are (1.22, 8.95).  That means the missile reaches a maximum height of 8.95 m after 1.22 seconds.

3) y = -0.04x² + 0.88x

The maximum is at:

x = -0.88 / (2 × -0.04)

x = 11

The maximum height is:

y = -0.04(11)² + 0.88(11)

y = 4.84

The maximum height of the tunnel is 4.84 meters.

The maximum width is when y = 0.

0 = -0.04x² + 0.88x

0 = -0.04x (x − 22)

x = 22

The maximum width is 22 feet.

7 0
4 years ago
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