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3 years ago

Paul works at a gas station. He earns $9.00 per hour.

Mathematics

2 answers:

cupoosta [38]3 years ago

8 0

Answer:

its 72

Step-by-step explanation:

lapo4ka [179]3 years ago

5 0

If Paul earns $9 an hour and works for 8 hours he would earn $72 a day. if you multiply 9 and 7 you get 72.

You might be interested in

Suppose that you are examining the difference in ages between brides and grooms. You are interested in conducting a significance

lesya [120]

Answer:

Parameter = 0.5

Null hypothesis : H0 : P0 = 0.5

Alternative hypothesis ; H0 : P0 > 0.5

Pvalue = 0.99966

Step-by-step explanation:

The parameter defines a statistical value or calculation which is derived from the population.

The parameter in this scenario is the population proportion, P0 which is 0.5

The scenario above describes a scenario to test the difference in population.

The null hypothesis, that bride and groom are of the same age ;

H0 : P0 = 0.5

The alternative hypothesis ; the bride is younger Than the groom in more than half of the population.

H1 : p0 > 0.5

To obtain the Pvalue :

Test statistic : (phat - P0) ÷ √(p0(1 -p0) / n)

Phat = x/n

x = 67 ; sample size, n = 100

Phat = x / n = 67/100 = 0.67

P0 = 1 - 0.5 = 0.5

Tstatistic = (0.67-0.50) ÷ √(0.5(0.5) / 100)

Tstatiatic = 0.17 ÷ 0.05

Tstatistic = 3.4

P-value : p(Z < 3.4) = 0.99966 (Z probability calculator).

5 0

3 years ago

Use the original price and the markdown to find the retail price.

ziro4ka [17]

Answer:

$33.6.

Step-by-step explanation:

40 x .16 = 6.4

40 - 6.4 = 33.6.

Feel free to let me know if you need more help. :)

4 0

3 years ago

Evaluate the function for f(5)=4x+3 A. 23 B. 22 C. 18 D. 7

Reptile [31]

Answer:

B. 22

Step-by-step explanation:

Hope this helps! Ask me anything if you have any quistions!

6 0

4 years ago

10 snails is to be chosen from this population. Find the probability that the percentage of streaked-shelled snails in the sampl

Alex17521 [72]

Here is the full question:

$The \ shell \ of \ the \ land \ snail \ Limocolaria \ martensiana \ has \ two \ possible \ color$ $forms: \ streaked \ and \ pallid. \ In \ a \ certain \ population \ of \ these \ snails, \ 60\% \ o f \ the$ $individuals \ have \ streaked \ s hells.\ 16 \ Suppose \ that \ a \ random \ sample \ of \ 10 \ snails$ $is \ to \ be \ chosen \ from \ this \ population. \ F ind \ the \ probabilit y \ that \ the \ percentage \ of$

$streaked-shelled \ snails \ in \ t he \ sample \ will \ be$

$(a) 50\%. \ (b) 60\%. \ (c) 70\%.$

Answer:

(a) 0.2007

(b) 0.2510

Step-by-step explanation:

Given that:

The sample size = 10

Sample proportion= 60% 0.6

Let X represents the no of streaked-shell snails.

$X \sim Binom (n =1 0, p = 0.60)$

The Probability mass function (X) is:

$P(X =x)= (^n_x) p^x(1-p)^{n-x}; x = 0,1,2,3...$

The Binomial probability with mean μ = np

= 10 * 0.6

= 6

Standard deviation σ = $\sqrt{np(1-p)}$

= $\sqrt{10*0.6*(1-0.6)}$

= 1.55

The probability that the percentage of the streaked-shelled snails in the sample will be:

$P(X = 0.5) = ^nC_x p^x (1 -p) ^{(n-x)}$

$= ^{10}^C_5 * (0.6)^5(1-0.6)^{10-5}$

$= \dfrac{10!}{5!(10-5)!} * (0.6)^5(1-0.6)^{10-5}$

= 0.2007

$P(X = 0.6) = ^nC_x p^x (1 -p) ^{(n-x)}$

$= ^{10}^C_6 * (0.6)^6(1-0.6)^{10-6}$

$= \dfrac{10!}{6!(10-6)!} * (0.6)^6(1-0.6)^{10-6}$

= 0.2510

$P(X = 0.7) = ^nC_x p^x (1 -p) ^{(n-x)}$

$= ^{10}^C_7 * (0.6)^7(1-0.6)^{10-7}$

$= \dfrac{10!}{7!(10-7)!} * (0.6)^7(1-0.6)^{10-7}$

= 0.2150

7 0

3 years ago

What is the value of x?

Nikolay [14]

Answer: 7 centimeters

Explanation:

Let triangle ABC and triangle CDE form a bow tie such that
- triangle ABC is smaller than triangle CDE
- Segment AC and segment CD are the north sides
- Segment BC and segment CE are the bottom sides
- AC = 6, CD = 42, CE = 36, BC = x

Since angle ACB and angle ECD are formed by intersecting segment AE and segment BD at point C, they are vertical angles. (See the attached picture) So, angle ACB and angle ECD are congruent.

Moreover when we form our bowtie, point A is in the north side and point E is in the bottom sides and this implies that angle BAC and angle CED are alternate interior angles as shown in the attached figure.

Since it is given in the problem that alternating interior angle are congruent, angle BAC and angle CED are congruent.

Now, we have the following pairs of angles in triangle ABC and triangle CDE that are congruent:

- angle BAC and angle CED
- angle ACB and angle ECD

By AA Similarity theorem, when we have two pairs of congruent angles for two triangles, then the two triangles are similar. So, triangle ABC and triangle CDE are similar.

In similar triangles, the sides that are opposite to the congruent angles are proportional to each other. So,

$\frac{BC}{CD} = \frac{AC}{CE} 


$ (1)

Since $AC = 6, CD = 42, CE = 36, BC = x$ , we can substitute these values to equation (1). So, equation (1) becomes

$\frac{x}{42} = \frac{6}{36}$
$\frac{x}{42} = \frac{1}{6}$ (2)

SInce we are solving for x, we can multiply both sides of equation (2) by the denominator at the left side which is 42 so that

x = 42(1/6)
x = 7 centimeters

8 0

3 years ago