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Oksana_A [137]
3 years ago
5

Find the value of x.

Mathematics
1 answer:
Dominik [7]3 years ago
6 0
X+16+3x-1+6x+5x=360 (because sum of exterior angles of all quadrilaterals or any other geometric figures is always 360)
=>15x=360-16+1
=>15x=345
=>x=23
Good luck!
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Divide ratio <br><br> £360 in the ratio 1 : 8
lianna [129]
Answer --> 40 : 320

1/9 x 360 = 40
8/9 x 360 = 320
3 0
3 years ago
A certain bowler can bowl a strike 85 % of the time. What is the probability that she ​a) goes three consecutive frames without
Artist 52 [7]

Answer:

a) 0.34% probability that she goes three consecutive frames without a​ strike.

b) 1.91% probability that she her first strike in the third ​frame

c) 99.66% probability that she has at least one strike in the first three ​frames.

d) 14.22% probability that she bowls a perfect game.

Step-by-step explanation:

For each frame, there are only two possible outcomes. Either there is a strike, or there is not. The probability of a strike happening in a frame is independent of other frames. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain bowler can bowl a strike 85 % of the time.

This means that p = 0.85

a) goes three consecutive frames without a​ strike?

This is P(X = 0) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.85)^{0}.(0.15)^{3} = 0.0034

0.34% probability that she goes three consecutive frames without a​ strike.

​b) makes her first strike in the third ​frame?

No strike during the first two(with a 15% probability)

Strike during the third(85% probability). So

P = 0.15*0.15*0.85 = 0.0191

1.91% probability that she her first strike in the third ​frame

c) has at least one strike in the first three ​frames? ​

Either there are no strikes, or there is at least one strike. The sum of the probabilities of these events is 100%.

From a), 0.34% probability that she goes three consecutive frames without a​ strike.

100 - 0.34 = 99.66

99.66% probability that she has at least one strike in the first three ​frames.

d) bowls a perfect game​ (12 consecutive​ strikes)?

This is P(X = 12) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{12,12}.(0.85)^{12}.(0.15)^{0} = 0.1422

14.22% probability that she bowls a perfect game.

3 0
4 years ago
in class of 24 students sold over 150 raffle tickets each, and the rest of the class sold about 60 raffle tickets each. the clas
Murrr4er [49]
They reached their goal because 150x24= 3,600 and that is much more than the class goal of 2,000 plus the 60 extra tickets the rest of the class sold. 
7 0
3 years ago
Read 2 more answers
Question Progress
andreyandreev [35.5K]

The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

Step-by-step explanation:

The given is,

                  The sum of two numbers is 21

                   The second number is six times the first number

Step:1

          Let, m - First number

                  n - Second number

Step:2

        From given,

                  n - 6m     ( The second number is six times the first number )

        Equation becomes,

                  Sum = m + n

        Where,

                      21 = m + ( 6m )

                       21 = 7m

                       m = 3

        Substitute m value n becomes,

                        n = 6m

                           = (6 × 3)

                      n  = 18

Result:

          The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

                   

5 0
3 years ago
Evaluate 5x if x= -5
Wittaler [7]
-25

Tell me if you need an explanation
5 0
4 years ago
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