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salantis [7]
3 years ago
12

+ 5 = 7" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
4 0
2x + 5 =7
Subtracting 5 from both sides
= 2x +5-5 = 7-5
=2x = 2
= x = 2/2
=x = 1
liraira [26]3 years ago
3 0
Yeah, your right cause you js use a calculator 2x+5=7
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The sum of two numbers is 41. The larger number is one less than twice the smaller number. Find the numbers.
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14 and 17

Step-by-step explanation:

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Please help me on this problem
Anna71 [15]

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The pairs of integer having two real solution forax^{2} -6x+c = 0 are

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  2. a = 1, c = 6
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  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

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3 years ago
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Answer:

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Step-by-step explanation:

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