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salantis [7]
3 years ago
12

+ 5 = 7" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Lera25 [3.4K]3 years ago
4 0
2x + 5 =7
Subtracting 5 from both sides
= 2x +5-5 = 7-5
=2x = 2
= x = 2/2
=x = 1
liraira [26]3 years ago
3 0
Yeah, your right cause you js use a calculator 2x+5=7
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Consider the triangle A(4,0), B(-2,4), C(0,6)<br> What will be the equation of the altitude BM?
katovenus [111]

Answer:

BM: <u>y = (2/3) x + 16/3</u> with segment length of 2.77

Step-by-step explanation:

AC formula: m = (6-0)/(0-4) = -3/2

(y-0)/(x-4) = -3/2       y = (-3/2)x + 6   ... (1)

BM slope: BM⊥ AC   m = 2/3

BM formula: (y-4) / (x- -2) = (y-4) / (x+2) = 2/3

y-4 = 2/3 x + 4/3

<u>y = (2/3) x + 16/3</u>   ... (2)    -2≤x≤0.31

intercept of AC and BM (M) from (1) and (2): (-3/2)x + 6 = (2/3) x + 16/3

(13/6) x = 2/3      x = (2/3) / (13/6) = 4/13 ≈ 0.31

y = (2/3) (4/13) + (16/3) = (8/39) + (208/39) = 216/39 = 72/13 ≈ 5.54

M (4/13 , 72/13) or (0.31 , 5.54)

segment BM = √(4/13 - -2)² + (72/13 - 4)² = √1300/169 = 2.77

4 0
2 years ago
Find the next three terms of the sequence. Then write a rule for the sequence.
g100num [7]
We notice it diviides by 3 each time or multiplies by 1/3
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first term is 648

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rule is an=648(1/3)^(n-1)
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3 years ago
-39.85 + 34.8 - .375
Monica [59]
I believe it is -5.425
8 0
3 years ago
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suter [353]
The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.

So we will approach this is in two ways.

If this was meant to be "divided by" then it would look like this:
6 / 192

If this was meant to be "divided to" then it would look like this:
192 / 6

Let us first solve for the first possible problem:
6 / 192 = ?
0.0312

0.0312 would be the answer.

Let us then solve for the second possible problem:
192 / 6 = ?
32 = ?

32 would be the answer.

So 0.0312 and 32 would be two possible answers to this problem.
4 0
3 years ago
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PLEASE HELP ME WITH NUMBER 1
LenaWriter [7]

hyp*2 = opp*2 + adj*2

c*2 = a*2 + b*2

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5 0
2 years ago
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