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Damm [24]
4 years ago
5

24x + 15 find the value of x​

Mathematics
1 answer:
nika2105 [10]4 years ago
5 0

Answer:

x=-0.625

Step-by-step explanation:

24x+15=0

     -15   -15

24x=-15

x=-0.625

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Solve<br><br> 9x^2 + 42x + 49 = 0
svet-max [94.6K]

Because of the relatively large coefficients {9, 42, 49}, applying the quadratic formula would be a bit messy. Instead, I've chosen to "complete the square:"


9x^2 + 42x + 49 = 0 can be re-written as 9 [ x^2 + (42/9)x ] = -49


Dividing both sides by 9, we get [ x^2 + (42/9)x ] = - 49/9


Completing the square: [ x^2 + (42/9)x + (21/9)^2 - (21/9)^2 ] = -49/9

[ x + 21/9 ]^2 = 441/81 - 441/81 = 0


Then [ x + 21/9 ] = 0, and x = -21/9 (this is a double root).

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Please answer, i'm timed (EDGE 2022)
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Last one: 3(x) - 3(9)

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6 0
2 years ago
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Find the measure of an angle whose supplement is six times its complement. Hint: The supplement and complement of an angle are (
sveticcg [70]

Let us translate the statements in the problem to mathematics equations

Let the angle is x degree

So its supplement is

180^{\circ}-x

And its complement is

90^{\circ}-x

Since the supplement is 6 times its complement, so Multiply the complement by 6 and equate the answer by the supplement

180-x=6(90-x)

Let us simplify the right side

180\text{ - x = 6(90) - 6(x)}180\text{ - x = 540 - 6x}

Now let us solve the equation to find x

At first, add 6x to both sides to put x in the left side

\begin{gathered} 180\text{ - x + 6x = 540 - 6x + 6x} \\ 180\text{ + 5x = 540} \end{gathered}

Now subtract 180 from both sides to put the number in the right side

\begin{gathered} 180\text{ - 180 + 5x = 540 - 180} \\ 5x\text{ = 360} \end{gathered}

Divide both sides by 5 to get x

\begin{gathered} \frac{5x}{5}=\frac{360}{5} \\ x=72^{\circ} \end{gathered}

So the measure of the angle is 72 degrees

You can check the answer

180 - 72 = 108

90 - 72 = 18

18 * 6 = 108

So the supplement of 72 is six times its complement

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1 year ago
Write 3x = 66 as a logarithmic function.
Musya8 [376]
Log(3) + log(x)=log(66)
log(x)=log(66)-log(3)
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