Because of the relatively large coefficients {9, 42, 49}, applying the quadratic formula would be a bit messy. Instead, I've chosen to "complete the square:"
9x^2 + 42x + 49 = 0 can be re-written as 9 [ x^2 + (42/9)x ] = -49
Dividing both sides by 9, we get [ x^2 + (42/9)x ] = - 49/9
Completing the square: [ x^2 + (42/9)x + (21/9)^2 - (21/9)^2 ] = -49/9
[ x + 21/9 ]^2 = 441/81 - 441/81 = 0
Then [ x + 21/9 ] = 0, and x = -21/9 (this is a double root).
The first one.
All 3 notes transitioned one bar line above it’s original placement. Hope this helps:)
Let us translate the statements in the problem to mathematics equations
Let the angle is x degree
So its supplement is

And its complement is

Since the supplement is 6 times its complement, so Multiply the complement by 6 and equate the answer by the supplement

Let us simplify the right side


Now let us solve the equation to find x
At first, add 6x to both sides to put x in the left side

Now subtract 180 from both sides to put the number in the right side

Divide both sides by 5 to get x

So the measure of the angle is 72 degrees
You can check the answer
180 - 72 = 108
90 - 72 = 18
18 * 6 = 108
So the supplement of 72 is six times its complement
Log(3) + log(x)=log(66)
log(x)=log(66)-log(3)
log(x)=log(66/3)
log(x)=log(22)
x=22