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Hoochie [10]
3 years ago
10

UM ANY help pls? Hopely someone can help!

Mathematics
2 answers:
vesna_86 [32]3 years ago
6 0

Answer:

He made 35% of his shots he did not make 65& of his shots

Step-by-step explanation:

7/20=35%, 20/7=65%

kompoz [17]3 years ago
5 0
Made 35%
Missed 65%
I hope this helps :)
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Triangle EFG is dilated by a scale factor of 2/3 to form triangle E'F'G'. What is the measure of side FG?
Illusion [34]

Answer:

Step-by-step explanation:

Since, the given question is incomplete but to solve these kind of questions,

Use the formula of the scale factor,

Scale factor = \frac{\text{Length of one dimension of the dilated image}}{\text{Length of one dimension of the preimage}}

From the question ΔE'F'G' is the image formed by the dilation of preimage ΔEFG.

Therefore, \frac{2}{3}=\frac{F'G'}{FG}

FG = \frac{3}{2}(F'G')

By substituting any value of F'G' given in the question we can evaluate the measure of side FG.

4 0
3 years ago
a large container holds 5 gallons of water it begins to leak at a constant rate after 10 minutes the container has 3 gallons of
Bad White [126]

Answer:

The container will take 25 minutes to go from full to empty.

https://socratic.org/questions/a-large-container-holds-5-gallons-of-water-it-begins-leaking-at-a-constant-rate-#323654

6 0
3 years ago
Anyone know how to do this if so can you explain
krek1111 [17]

Answer:

the answer is -0.5/

-  \frac{1}{2}

8 0
3 years ago
13. A certain town with a population of 100,000 has 3 newspapers: I, II, and III. The proportions of townspeople who read these
Lina20 [59]

Answer:

24,000 people read only one newspaper

12,000 people read at least two newspapers

11,000 people read at least one morning paper plus an evening paper.

64,000 people do not read any newspapers.

10,000 people read only one morning paper and one evening paper.

Step-by-step explanation:

The problem states that:

- 10 percent of the population reads the newspaper I = 10,000

- 8 percent of the population reads the newspaper I and II = 8,000

- 1 percent of the population reads the newspaper I and II an III = 1,000

- 30 percent of the population reads the newspaper III = 30,000

- 2 percent of the population reads the newspaper I and III = 2,000

- 5 percent of the population reads the newspaper III = 5,000

- 4 percent of the population reads the newspaper II and III = 4,000.

Then we have to build the Venn diagram for this: I am going to call

- A the people that read the newspaper I

- B the people that read the newspaper II

- C the people that read the newspaper III

We start this from the people that read each newspaper

A \cap B \cap C = 1,000 - 1,000 people read each newspaper

The people that read only I and II are the number of people that read I and II minus the number of people that read I, II and III. So:

A \cap B = 8,000 - A \cap B \cap C = 8,000 - 1,000 = 7,000

It applies for I and III

A \cap C = 2,000 - A \cap B \cap C = 2,000 - 1,000 = 1,000

And for II and III

B \cap C = 4,000 - A \cap B \cap C = 4,000 - 1,000 = 3,000

The problem states that 10,000 people read the newspaper I, so:

A + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 10000 where A is the number of people that read only the newspaper I. So:

A + 7,000 + 1,000 + 1,000 = 10,000

A + 9,000 = 10,000

A = 1,000

30,000 read the newspaper II, so:

B + (A \cap B) + (B \cap C) + (A \cap B \cap C) = 30,000

B + 7,000 + 3,000 + 1,000 = 30,000

B + 11,000 = 30,000

B = 19,000

5,000 read the newspaper III, so:

C +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 5,000

C + 1,000 + 1,000 + 1,000 = 5,000

C = 2,000

The answers:

a) Find the number of people who read only one newspaper

A + B + C = 1,000 + 21,000 + 2,000 = 24,000

24,000 people read only one newspaper

b) How many people read at least two newspapers

(A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C) = 7,000 + 1,000 + 3,000 + 1,000 = 12,000

12,000 people read at least two newspapers

If I and III are morning papers and II is an evening paper, how many people read at least one morning paper plus an evening paper?

(A \cap B) + (B \cap C) + (A \cap B \cap C) = 7,000 + 3,000 + 1,000 = 11,000

11,000 people read at least one morning paper plus an evening paper.

How many people do not read any newspapers?

There is 100,000 people in the town.

So, the number of people that does not read any newspaper is:

100,000 - (A + B + C + (A \cap B) +  (A \cap C) + (B \cap C) + (A \cap B \cap C)) = 100,000 - 36,000 = 64,000

64,000 people do not read any newspapers.

How many people read only one morning paper and one evening paper?

(A \cap B) + (B \cap C) = 7,000 + 3,000 = 10,000

10,000 people read only one morning paper and one evening paper.

3 0
3 years ago
How many rectangles can you build with a prime number of square tiles?
zalisa [80]
You can only make one rectangle but that is assuming orientation does not matter and still counts as one. For example, a 3 by 1 and a 1 by 3 is the same rectangle but has different orientations so in essences there are two but really just one
7 0
4 years ago
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