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ASHA 777 [7]
2 years ago
7

Monique randomly surveyed 30 students from

Mathematics
1 answer:
Naily [24]2 years ago
8 0

Answer:

522

Step-by-step explanation:

Find the percent of students in her class that have a dog or cat:

  1. Set up a proportion: \frac{18}{30} = \frac{x}{100}  
  2. Cross multiply, then divide: 18 × 100 = 1800, 1800 ÷ 30 = 60
  3. So, 60% have a dog or cat

Find 60% of the total amount of students in Monique's school:

  1. 60% of 870 = \frac{60}{100} × \frac{870}{1}  
  2. \frac{60}{100} × \frac{870}{1} = \frac{52200}{100}  
  3. \frac{52200}{100} = \frac{522}{1} = 522  

I hope this helps!

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A Cab charges $1.75 for the flat fee and $0.25 for each mile. Write and solve an inequality to determine how many miles Eddies c
NemiM [27]
1.75 + 0.25x ≤ 15
where x is equal the number of miles.

The key to solving an inequality is just temporarily making the ≤ symbol a =. Then solve for x like any other algebraic equation. Once you find the value of x, you will have solved the inequality. Make sure to add back the ≤ when you are done. 

15 - 1.75 = 13.25
13.25/0.25 = x 
x = 53
add back the ≤
x ≤ 53
This means Eddies can travel up to 53 miles with his $15.
4 0
3 years ago
Could someone help with a maths question? The attachment has the questions on it.
andre [41]

The days she has recorded: 11 + 10 + 7 + 6 + 3 + 2 = 39
The mode distance (most often): 5 km
Median distance: 6.64 km ~= 6.5 km ~= 7 km by rounding upwards, so 3rd

Cumulative frequency: 11; 21; 28; 34; 37; 39

7 0
2 years ago
A total of 646 tickets were sold. They were either adult ticket or student tickets. There were 54 fewer student tickets sold tha
Firdavs [7]

Answer:

350

Step-by-step explanation:

Let the number of adult tickets be x, then the number of student tickets sold would be (x–54).

We now have

x+(x–54)=646

2x=700

x=350

Therefore, 350 adult tickets were sold.

6 0
2 years ago
6x7=(6x5)+(6x2). Of which multiplication property?
tresset_1 [31]
This is the<u> distributive property of multiplication</u> but tricky
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5 0
3 years ago
Read 2 more answers
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
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