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3 years ago

What is the slope of a line perpendicular to the line whose equation is x+y=2

Mathematics

1 answer:

vodomira [7]3 years ago

5 0

Answer:

x+y-2=0

Step-by-step explanation:

thats ur anwser you are welcome:)

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N trapezoid ABCD, find m∠A if m∠B= 25°, m∠C = 155° and m∠ D= 117°. A) 25° B) 63° C) 73° D) 92°

ExtremeBDS [4]

Sum of the angles of the trapezoid (quadrilateral) add up to 360Â°, so based on available information
mâ A + mâ B + mâ C + mâ D = 360Â° relates to mâ A + 25Â° + 155Â°
+ 117Â°.=360Â°
So, mâ A = 360Â° - (25Â°+155Â°+117Â°)
mâ A = 360Â° - 297Â°
mâ A = 63Â°

3 0

3 years ago

What is the lcm of 6 12 and 15

Helga [31]

6, 12 18 24 30 36 42 48 54 60...
12, 24 36 48 60...
15, 30 45 60...

Voila. 60 shows up in all three. Its the first one to show up, hence lcm (least common multiple)

3 0

3 years ago

Write the equation of the line in fully simplified slope-intercept form.

Bad White [126]

Answer:

$y = -\frac{2}{5} x-6$

Step-by-step explanation:

1) First, find the slope of the line. Use the slope formula $m =\frac{y_2-y_1}{x_2-x_1}$ . Pick two points on the line and substitute their x and y values into the formula, then solve. I used the points (-5,-4) and (0,-6):

$m = \frac{(-6)-(-4)}{(0)-(-5)} \\m = \frac{-6+4}{0+5} \\m = \frac{-2}{5} \\$

So, the slope of the line is $-\frac{2}{5}$ .

2) Next, use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation of the line in point-slope form. (From there, we can convert it to slope-intercept form.) Substitute values for the $m$ , $x_1$ and $y_1$ into the formula.

Since $m$ represents the slope, substitute $-\frac{2}{5}$ in its place. Since $x_1$ and $y_1$ represent the x and y values of one point on the line, pick any point on the line (any one is fine, it will equal the same thing at the end) and substitute its x and y values in those places. (I chose (0,-6), as seen below.) Then, with the resulting equation, isolate y to put the equation in slope-intercept form:

$y-(-6) = -\frac{2}{5} (x-(0))\\y + 6 = -\frac{2}{5} x\\y = -\frac{2}{5} x-6$

6 0

3 years ago

Only 21% of the candidates who apply for an MBA program in a university are called for an interview, and only 5% of those who ar

artcher [175]

Answer:

9999999999999999

Step-by-step explanation:

4 0

3 years ago

The vertices of a square CDEF are C(1,1), D(3,1), E(3,-1) and F(1,-1). What formulas prove that the diagonals are congruent perp

Oxana [17]

To prove that the diagonals are congruent, you need to formula to compute the distance between two points:

$d(A,B) = \sqrt{(A_x-B_x)^2 + (A_y-B_y)^2}$

Using that formula, you may prove that $d(C,E) = d(D,F)$ , which means that the two diagonals have the same length.

To prove that they are perpendicular, you need the formula to compute the slope of a segment. The slope, knowing the enpoints, is given by

$m = \cfrac{\Delta y}{\Delta x} = \cfrac{A_y-B_y}{A_x-B_x}$

You can use this formula to prove that

$m_{CE} = -\cfrac{1}{m_{DF}}$

In fact, if one slope is the opposite of the reciprocal of the other, the two segments are perpendicular.

Finally, to prove that they bisect each other, you first need to find the point where they meet. First of all, you need to find the line the segments lie on: the formula is

$y-y_0 = m(x-x_0)$

where $(x_0,y_0)$ is one of the points belonging to the line, and you already know how to find the slope. Then, you find the point of intersection, say A, by solving the system involving the two lines:

$\begin{cases} y= m_{CE}x+q_{CE}\\ y = m_{DF}x+q_{DF} \end{cases}$

And use again the formula for the distance between two points to prove that

$d(A,C) = d(A,D) = d(A,E) = d(A,F)$

4 0

3 years ago