“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
To solve this, the problem is solvable by elimination. So you see how the 5y and -5y cancel out? You basically add those two and you add the -7x and 4x and 10 and -10 leaving you with -3x=0. Dividing by each side gives you x=0. Then, plug 0 in for x in -7x+5y=10. Giving you
-7(0)+5y=10.
0+5y=10
5y=10
Divide by 5 on each side giving you y=2. So your answer is (0,2).
Answer:
x = 13
Step-by-step explanation:
Here, we want to get the missing side
from what we have, the triangle is a right angled triangle
In this kind of triangle, the Pythagoras’ theorem works
The square of the side facing the right angle ( marked x here) is equal to the sum of the squares of the two other sides
We have this as;
x^2 = 5^2 + 12^2
x^2 = 25 + 144
x^2 = 169
x = √169
x = 13
The standard form is 5x-6y=16
