Ask question

Ask question

All categories

3 years ago

14

HELPPPPPPP MEEEEEEE PLEASE

2 answers:

Ira Lisetskai [31]3 years ago

8 0

7. The answer is Airline 1. 8. The answer is 6/4/13. 5. 50+35 times n. 6. Bottom axis could be Number of People and left axis could be Cost of Family

sineoko [7]3 years ago

5 0

Take a better pic I can’t seee

You might be interested in

Each week samantha can pay as much as $15 for her school lunch. Write an inequality showing how much samantha spends on lunch.

Annette [7]

Answer:

$x\leq \$15$

Step-by-step explanation:

Let

x------> amount of money that Samantha spends weekly on her school lunch

we know that

The inequality that represent this situation is

$x\leq \$15$

All positive real number less than or equal to 15

5 0

3 years ago

Is -0.28764 rational or irrational and how do you figure that out?

kvv77 [185]

It is rational. Any number that can be described as a fraction is rational while those that do not are irrational.

-0.28764 is the same as -(28764/100000) and positive, negative does not matter.

8 0

3 years ago

A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ <em> (Approximated)</em>

5 0

3 years ago

Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)

<u>Algebra II</u>

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

6 0

3 years ago

Please answer and work it out and round to the nearest tenth. Thank you!

Nataly [62]

The length of UV is 6 in because it is parallel to WX.

Find the length of TV:

$TV^{2} =\sqrt{TU^{2} +TV^{2}}$

$TV^{2} =\sqrt{12^{2} +6^{2}}$

$TV^{2} =\sqrt{144+36}$

$TV^{2} =\sqrt{180}$

$TV =6\sqrt{5} = 13.41640786$

The length of VX is 9 in because it is parallel to UW.

$TX^{2} =\sqrt{TV^{2} +VX^{2}}$

$TX^{2} =\sqrt{180 +9^{2}}$

$TX^{2} =\sqrt{180 +81}$

$TX^{2} =\sqrt{261}$

$TX =16.15549442$

<h2>TX = 16.2 inches</h2>

8 0

3 years ago

Read 2 more answers