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Stells [14]
3 years ago
13

Christine manages a car wash. The owner of the car wash thinks they could be making bigger profits. Christine looks for ways to

cut costs and increase profits. To solve this problem, Christine should _____. create a spreadsheet to track costs for the past month create a spreadsheet with current costs and use it to generate ideas about cutting costs create a balance sheet create a scatter graph
Business
1 answer:
NikAS [45]3 years ago
6 0

Answer:

The correct option is;

Create a spreadsheet to track costs for the past month    

Explanation:

In order to cut costs and reduce spending, it is important to track the costs and the expenditures of the car wash for the previous month such that the excess cost or expense items can be detected and the likelihood of engaging in overspending in the future is reduced because the manager is paying attention to and cautious about the costs incurred while running the carwash

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Preston Industries has two separate divisions. Each division is in a separate line of business. Division A is the largest divisi
bogdanovich [222]

Answer:

D. assign appropriate, but differing, discount rates to each project and then select the projects with the highest net present values.

Explanation:

Even though Division A is the largest and produce the highest amount of sales, it will not be selected based on this factor but its net present value(NPV). This will determine if the sales actually can fully recover the initial investment amount and yield a profit. Therefore, since Division A and B have different levels of risk, it will be appropriate to find their NPVs using different discount rates and accept the one with the highest NPV.

8 0
3 years ago
An attendant at a car wash is paid according to the number of cars that pass through. Suppose the probabilities are 1/12, 1/12,
Paladinen [302]

Answer: The attendant’s expected earn- ings for the period between 4:00 P.M and 5:00 P.M is <u>$12,67.</u>

Explanation: <u>The discrete random variable X</u> represent attendant’s earnings.

The expected value of the discrete random variable X is

<h2>= E (x) = ∑× f(x)</h2><h2>= 7 × 1/12 + 9 × 1/12 + 11 × 1/4 + 13 × 1/4 + 15 × 1/6 + 17 × 1/6 = <u>12,67.</u></h2><h2><u /></h2>
5 0
3 years ago
to answer this question. In week 1 the inventory manager discovers, much to his horror, that instead of 65 tacos in inventory, t
rodikova [14]

Answer:

D.110

Explanation:

They had 6.5 instead of 65.

Number of production shortage

65/6.5=10

Now this is equal to 10 × 10 + 10

=110

8 0
3 years ago
Purchased raw materials of $17,700 on account. (b) Incurred factory labor of $39,200. Of that amount, $29,400 relates to wages p
alekssr [168]

Answer:

Journal Entries:

a) Debit Raw materials inventory $17,700

Credit Accounts payable $17,700

To record the purchase of raw materials on account.

b) Debit Payroll expense $39,200

Credit Wages payable $29,400

Credit Payroll taxes payable $9,800

To record payroll expense.

c) Debit Factory utilities expenses $3,600

Credit Utilities payable $3,600

To accrue factory utilities expenses.

Debit Factory property taxes of $2,510

Credit Cash $2,510

To record payment of property taxes.

Debit Depreciation Expense, Factory building $9,600

Credit Accumulated Depreciation, Factory building $9,600

To record depreciation expense.

Explanation:

1) Data and Analysis:

a) Raw materials inventory $17,700 Accounts payable $17,700

b) Payroll expense $39,200 Wages payable $29,400 Payroll taxes payable $9,800

c) Factory utilities $3,600 Utilities payable $3,600

Factory property taxes of $2,510 Cash $2,510

Depreciation Expense, Factory building $9,600 Accumulated Depreciation, Factory building $9,600

3 0
2 years ago
The cost of controlling emissions at a firm goes up rapidly as the amount of emissions reduced goes up. Here is a possible model
Diano4ka-milaya [45]

Answer:

in order to minimize net cost, the firm needs to remove 2.5 pounds of x (reduction in sulfur) and 1 pound of y ( reduction in lead) each day

Explanation:

Given that;

C(x, y)= 4000+100x^2+50y^2

Subsidiary = 500x + 100y

The Net cost  C will be:

C = 4000+100x^2+50y^2 - (500x + 100 y)

For Critical point C_X ; by differentiating with respect to x alone;

C_X =0+100(2x)+0 - 500 - 0

C_X =200x - 500

For Critical point C_Y ; by differentiating with respect to y alone;

C_Y  = 0+0+50(2y) - 0-100

C_Y  =100 y -100

For minimum cost C_X= 0

200x - 500 = 0

200x = 500

x = 500/2

x = 5/2

x = 2.5

For minimum cost C_Y = 0

100y - 100 = 0

100 y = 100

y = 1

Hence; in order to minimize net cost, the firm needs to remove 2.5 pounds of x (reduction in sulfur) and 1 pound of y ( reduction in lead) each day

4 0
3 years ago
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