Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
ln 5
e = ?
x
Keep in mind that y=e and y = ln x are inverse functions of one another.
ln 5
e , we can drop both the "e" and the "ln 5." We are left with 5 (answer).
ln 5
Alternatively, we could take the ln of both sides of y = e
which will result in ln y = (ln 5) ln e. Note that ln e = 1 (these two functions are inverses of one another).
Then we are left with ln y = ln 5. Dropping the "ln" operator from both sides,
y=5 (same as before).
The answer is c. 64 divided by 4 is 16 and 8 divided by 5 is 16
Answer:
a=7
Step-by-step explanation:
24^2+a^2=25^2
576+a^2=625
49=a^2
a=7
