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aliya0001 [1]
3 years ago
7

Hi pls help. pls explain a bit thank you:)

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

a^3b^2c^6

Step-by-step explanation:

n^x*n^y=n^{x+y}

so

a^6*a^{-3}*a^0=a^{6-3+0}=a^3

b^3*b^1*b^{-2}=b^{3+1-2}=b^2

c^4*c^2=c^{4+2}=c^6

put it all together

a^3b^2c^6

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The answer is 3 hope this helps
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3 years ago
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fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula
OleMash [197]
Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²

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7 0
3 years ago
The recommended dosage for ceclor (cefaclor) is 30mg/kg to be given P.O. for a child weighing 32 lbs. Available: 125mg/5ml. How
andreyandreev [35.5K]

The child's weight in kilogram (kg) is equal to 14.5 kilogram. 2. The safe 24-hour dosage range for this child is 290 mg to 580 mg.

Given that the recommended dosage for ceclor is 30mg/kg to be given P.O. for a child weighing 32 lbs.

In order to determine the weight of the child, we would convert the value of the child's weight in pounds (lbs) to kilogram (kg) as follows:

1 pound = 0.4536 kilogram

32 pound = x kilogram

Cross-multiplying, we have: X = 32 × 0.4536 Child's weight, x = 14.5 kilogram.

Minimum range = 30 × 14.5 = 290 mg to 580 mg

Maximum range = 125 × 14.5 = 580 mg

Therefore, the safe 24-hour dosage range for this child is 290 mg to 580 mg.

Hence based on the calculations, we can infer and logically deduce that yes the dosage ordered safe because the safe single dose range is from 97 mg to 193 mg.

learn more about safe dosage at brainly.com/question/13186642

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Complete Question:

Ceclor (cefaclor) 100 mg p.oh is ordered for a child weighing 32 lbs.

1. What is the child's weight in kilograms (round to tenths)

2. What is safe 24-hour dosage range for this child?

3. Is the dosage ordered safe?

A. Yes

B. No, below the recommended dosage

C. No, it is for above the recommended dosage

D. More information is needed

4 0
2 years ago
A triangle is shown with its exterior angles. The interior angles of the triangle are angles 2, 3, 5. The exterior angle at angl
anastassius [24]

Answer:

<5 + <6 = 180 degrees

<2 + <3 = <6

<2 + <3 + <5 = 180 degrees

Step-by-step explanation:

6 0
3 years ago
An airplane is traveling due east with a velocity of 583 miles per hour. The wind blows at 75 miles per hour at an angle of S58°
ASHA 777 [7]

Answer:

  D. 647.8 miles per hour; S86.5°E

Step-by-step explanation:

We assume the wind direction is supposed to be S58°E. Then the bearing of the plane measured clockwise from north is 90°, and the direction the wind is blowing toward has a bearing of 122°. The resultant speed and direction is the sum of the two vectors, which is easily found using a suitable calculator:

  583∠90° + 75∠122° = 647.8∠93.5°

The bearing of 93.5° translates to the direction S86.5°E.

_____

An angle east of south is subtracted from 180° (south) to find the equivalent bearing.

7 0
3 years ago
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