Answer:
4.45 ccs will remain after 5 hours.
Step-by-step explanation:
The anti-biotic in his body decreases at a rate proportional to the amount, Q(t), present at time t.
(dQ/dt) = - kQ ((Minus sign because it's a rate of reduction)
(dQ/dt) = -kQ
(dQ/Q) = -kdt
∫ (dQ/Q) = -k ∫ dt
Solving the two sides as definite integrals by integrating the left hand side from Q₀ to Q and the Right hand side from 0 to t.
We obtain
In (Q/Q₀) = -kt
(Q/Q₀) = e⁻ᵏᵗ
Q(t) = Q₀ e⁻ᵏᵗ
the initial injection was 8 ccs and 5 ccs remain after 4 hours
Q₀ = 8 ccs,
At t = 4 hours, Q = 5 ccs
5 = 8 e⁻ᵏᵗ
e⁻ᵏᵗ = 0.625
-kt = In (0.625) = -0.47
-4k = 0.47
k = 0.1175 /hour
Q(t) = Q₀ e⁻⁰•¹¹⁷⁵ᵗ
At t = 5 hours, Q = ?
Q = 8 e⁻⁰•¹¹⁷⁵ᵗ
0.1175 × 5 = 0.5875
Q = 8 e(^-0.5875)
Q = 4.45 ccs
Hope this Helps!!!
Answer:15
Step-by-step explanation:
27+x=42
Collect like terms
x=42-27
x=15
Answer: C is the correct answer.
Step-by-step explanation: First of all, you have to eliminate the answer choice in which the angles are different for the cosine term and for the sine term. Therefore, you can eliminate choice D.
The way that complex numbers are written are the following:
z=a+bi
r (which is considered the magnitude/number outside the parentheses)=sqrt (a^2+b^2)
tan(angle)=b/a.
Now using the information given here,
a=-6, b=6.
r=sqrt ((-6)^2+6^2)=sqrt(72)=6sqrt2
tan(angle)=6/-6=>-1
angle is equal to arctan(-1)=3pi/4.
Therefore the correct answer is C. Hope that helped!
If the question had asked what is 9/9 closer to you would say 1. When you increase the numerator by one digit go higher than 1.
10/9 = 1.11111111
so it is closer to 1 than to anything else
Y=3x-5
Y=5/4x+3/4
The solution to the equations is in the picture
