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matrenka [14]
3 years ago
10

What is the solution to the system of equations below? -4x+6y=-18 and y=-2x+21

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

x=9 and y=3

Step-by-step explanation:

Let's solve your system by substitution.

−4x+6y=−18 and y=−2x+21

Rewrite equations:

y=−2x+21;−4x+6y=−18

Step: Solve  y=−2x+21for y:

y=−2x+21

Step: Substitute−2x+21foryin−4x+6y=−18:

−4x+6y=−18

−4x+6(−2x+21)=−18

−16x+126=−18(Simplify both sides of the equation)

−16x+126+−126=−18+−126(Add -126 to both sides)

−16x=−144

−16x

−16

=

−144

−16

(Divide both sides by -16)

x=9

Step: Substitute9forxiny=−2x+21:

y=−2x+21

y=(−2)(9)+21

y=3(Simplify both sides of the equation)

Answer:

x=9 and y=3

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A student's tuition was $5530. A loan was obtained for 4/7 of the tuition. How much was the loan?
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The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

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The quadratic equation is then calculated as

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Substitute the known values in the above equation

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Evaluate the products

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Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

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Step-by-step explanation:

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