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Dmitriy789 [7]
3 years ago
15

The table below shows how much Joe earns, y, after working x hours.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer: Given : Joe’s Earnings and hour worked

The relationship between money earned and hours worked is linear.

Joe computes the slope between (4, 30) and (12, 90), then computes the slope between (4, 30) and (10, 75).

To Find : How do the two slopes compare?

Solution:

Hours worked     Money earned

4                          $30

10                        $75

12                        $90

22                       $165

slope between (4, 30) and (12, 90),

= (90 - 30)/(12 - 4)

= 60/8

= 15/2

slope between (4, 30) and (10, 75)

= (75 - 30)/(10-4)

= 45/6

= 15/2

The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.

Both Slopes are same.

i hope this helped and have a nice day/night

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Please explain some more:)
4 0
3 years ago
The graph of a linear function passes through the point (-1, 2) and has a slope of 3. What is the equation of the function in sl
Harman [31]

Answer:

The equation of the function in slope-intercept form is y = 3 x + 5 .

Step-by-step explanation:

Given as :

A line passes through the point ( - 1 , 2 )

i.e ( x , y ) = ( - 1 , 2 )

The slope of the line is 3

The equation of line in slope intercept form

y - \textrm y_1 = m ( x - \textrm x_1 )

Where m is the slope of the line

So, y - 2 = 3 ( x - ( - 1 ) )

Or, y - 2 = 3 ( x + 1 )

Or, y - 2 = 3 x + 3

Or, y = 3 x + 3 + 2

∴   y = 3 x + 5

Hence The equation of the function in slope-intercept form is y = 3 x + 5 . Answer

8 0
3 years ago
What's the answer for this problem number 6 and how did you get your answer?
lorasvet [3.4K]

\frac{7}{b + 5} =  \frac{10}{5} \\

\frac{7}{b + 5} = 2 \\

Multiply the sides of the equation by ( b + 5 ) :

7 =2 \times (b + 5)

7 = 2b + 10

Subtract the sides of the equation minus 10 :

7 - 10 = 2b

- 3 = 2b

Divided the sides of the equation by 2 :

b =  -  \frac{3}{2}  \\

____________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
4 years ago
A local chicken farmer is constructing a set of eight pens to cage his chickens as shown in the diagram below. He has decided to
Vilka [71]
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²

Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.

A'(x)=3000-18X

Set derivative equal to 0

0=3000-18X
166.6666666=X

Now test the intervals

(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -

Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5

Answer:
X= 166.6666666666
Y=5

Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
6 0
3 years ago
Evaluate the expression if a = 4, b = 9, and c = 1.
uranmaximum [27]

Answer:

Given - a = 4

b = 9

c = 1

To find - Value of equation

Solution -

3b ÷ c^1 - a

Putting the value of a,b and c in the equation

3(9) ÷ (1)^1 - 4

27 ÷ 1 - 4

27 ÷ (-3)

27 × (1 /(-3)

27/(-3)

(-9)

3 0
3 years ago
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