Assuming AB is the height because we are given it has a square base with 4 by 4
so draw a diagram ( see attachment)
given tha the 8 inch straw ha 1 inch sticking out, the diagonal is 7
use pythagorean theorem twice since 2 right triangles
a^2+b^2=c^2
4^2+4^2=c^2
16+16=c^2
32=c^2
sqrt both sides
4√2=c
the bottom diagonal is 4√2
bottom^2+height^2=7^2
(4√2)^2+(AB)^2=7^2
32+(AB)^2=47
minus 32 both sides
(AB)^2=15
sqrt both sides
AB=√15
if AB is the height
Answer:
y = -2/3x + 1
Step-by-step explanation:
Step 1: Find slope
m = (-1 - 3)/(3 + 3)
m = -2/3
y = -2/3x + b
Step 2: Find <em>b</em>
-1 = -2/3(3) + b
-1 = -2 + b
b = 1
Step 3: Write equation
y = -2/3x + 1
Rectangle. it’s a 2d 4 sided shape with 2 sets of parallel sides
Answer:
cos 30°=b/h
<u>√</u><u>3</u><u>/</u><u>2</u><u>=</u><u>6</u><u>√</u><u>3</u><u>/</u><u>y</u>
<u>y=</u><u>6</u><u>√</u><u>3</u><u>/</u><u>√</u><u>3</u><u>/</u><u>2</u>
<u>y=</u><u>1</u><u>2</u>
Answer:
a.35.57%
b. 100.686
Step-by-step explanation:
To find the percentage of the test scores that exceeded 84, we need to standardize 84 as:
Where m is the mean of the scores and s is the standard deviation. Now, using the standard normal table, we can know the following probability:
P(Z > 0.37) = 0.3557
So, the percentage of the test scores that exceeded 84 were 35.57%
Now, to find the candidate's score that fell at the 98th percentile of the distribution we need to find th z-value that satisfies:
P(Z < z) = 0.98
So, using the standard normal table we have:
z = 2.06
Then, the candidate's score x is 100.686 and it is calculated as: