Answer:
The correct answer is-
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
2. Two genes, with a dominant allele at either or both loci.
Explanation:
The given information gives THE following data:
Dominant: Lancerate leaves - AABB
Recessive: normal leaves - aabb
F1 has - all Lacerated leaves - AaBb
F2 by selfing F1:
AB Ab aB ab
AB AABB AABb AaBB AaBb
Ab AABb AAbb AaBb Aabb
aB AaBB AaBb aaBB aaBb
ab AaBb Aabb aaBb aabb
Here, 15/16 = lacerate which is 0.94 which is equal to the value of lacerate given in the question - 249/265 = 0.94
And normal 1/16 = 0.062 is almost same as 16/265 = 0.060
Thus, the genotypes of -
F1 - AaBb (lacerate)
F2 - A_B_; A_bb; and aaB_ (lacerate)
- aabb (normal)
Answer: Point source
Explanation:
An exotoxin is a toxic substance secreted by bacteria. The botulism exotoxin is the exotoxin secretes by bacterial strain named as Clostridium botulinum.
Point source outbreak is a condition in which people are exposed to the same source of infection from a pathogen. This may occur due to the consumption of a single meal which is being infected by the pathogen. This may lead to incidences of food poisoning, disease and even mass death.
An allele. It’s a variant of a cell.
Since Jordan needs to use the high power objective in order to view the specimen under the light microscope. He should use the ocular lens in order to view the high power objective which is placed in the objective lenses. So he needs to use the ocular lens for viewing and the objective lens to magnify and see the specimen clearly on the stage.
